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Knowing that
log H
þ
pH
m
¼
ð
½
Þ
ð
30
Þ
H
þ
OH
K
w
¼
½
½
;
ð
31
Þ
Equation (
29
) can be then rewritten as:
210
pH
m
pK
a2
1
þ
ð
Þ
10
pH
m
14
10
pH
m
W
a4
þ
þ
W
b4
10
pH
m
pK
a2
¼
0
ð
32
Þ
10
pH
m
pK
a1
1
þ
þ
The mass balance yields to:
A
dh
dt
¼
q
1
þ
q
2
þ
q
3
q
4
ð
33
Þ
h
0
:
5
, Eq. (
33
) becomes:
Taking into account that the exit
fl
ow rate q
4
¼
C
v
:
A
dh
h
0
:
5
dt
¼
q
1
þ
q
2
þ
q
3
C
v
ð
34
Þ
where C
v
is the constant valve coef
cient.
The differential equations of the ef
fl
uent reaction invariants
ð
W
a4
;
W
b4
Þ
can be
determined as follows:
Ah
dW
a4
dt
¼
q
1
ð
W
a1
W
a4
Þþ
q
2
ð
W
a2
W
a4
Þþ
q
3
ð
W
a3
W
a4
Þ
ð
35
Þ
Ah
dW
b4
dt
¼
q
1
ð
W
b1
W
b4
Þþ
q
2
ð
W
b2
W
b4
Þþ
q
3
ð
W
b3
W
b4
Þ
ð
36
Þ
Nominal model parameters and operating conditions (Xiao et al.
2014
) are given
in Table
6
.
The static nonlinearity of this process can be represented by the titration curve
shown in Fig.
6
with a beginning pH of 2.7 and an ending pH of 10.7. A brief glance
at the curve indicates that the process of pH neutralization is highly nonlinear.
Table 6 Operation
parameters of the pH
neutralization process
q
1
¼
16
:
6ml/s
W
a1
¼ 3
10
3
mol/l
q
2
¼ 0
:
55ml/s
10
2
mol/l
W
a2
¼
3
q3 ¼ 15
:
6 ml/s
10
3
mol/l
W
a3
¼
3
:
05
h ¼ 14
:
0cm
W
b1
¼ 0
A ¼ 207 cm
2
10
2
mol/l
W
b2
¼ 3
C
v
¼ 8
:
75 ml/cm/s
10
5
mol/l
W
b3
¼ 5
pK
a1
¼
6
:
35
pH
4
¼
7
pK
a2
¼
10
:
25
s
¼
0
:
5
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