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∞
|φ
(
ω
+2
πr
)
2
=1
.
|
(8.36)
r
=
−∞
φ
(
t
)is
|φ
(
ω
)
2
and sampling a function periodizes its Fourier
transform. Equation (8.36) is true if we choose
This is because
φ
∗
|
1
a
(
ω
)=
.
∞
| N
n
(
ω
+2
πr
)
2
)
1
/
2
(
|
r
=
−∞
Using the above result we can write,
2
n
sin
n
ω/
2
e
−iβω/
2
φ
(
ω
)=
,
∞
| N
n
(
ω
+2
πr
)
2
)
1
/
2
|
ω
n
(
r
=
−∞
2
n
sin
n
ω/
2
e
−iβω/
2
(8.37)
=
,
∞
1
(
ω
+2
πr
)
2
n
)
1
/
2
ω
n
2
n
sin
n
ω/
2(
r
=
−∞
e
−iβω/
2
ω
n
√
S
2
n
,
=
where
∞
1
(
ω
+2
πr
)
2
n
,
S
2
n
=
(8.38)
r
=
−∞
d
2
n−
1
1
2
2
n
1
=
−
dx
2
n−
1
cot
x.
(2
n
−
1)!
Example 1: Linear splines
For linear splines, the order of the polynomial is
n
=2.Alsowhen
n
is even,
β
=0and
β
= 1 when
n
is odd. Hence, from equation (8.38),
1+2cos
2
x
sin
4
x
S
4
(
ω
)=
1
48
.
Therefore,
√
1+2cos
2
x
sin
2
x
S
4
(
ω
)=
1
4
√
3
,
and so,
4
√
3sin
2
x
√
1+2cos
2
x
.
1
ω
2
φ
(
ω
)=
Example 2: Cubic splines
For cubic spline,
n
= 4. Hence, from equation (8.38),
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