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n− 1
2 λ r cos ω + λ r
|
1
1
| N n ( ω +2 πr )
2 =
|
,
(2 n
1!)
λ r |
r = −∞
r =1
since λ r s are negative and
1
cos ω
1wehave,
| N n ( ω +2 πr )
2
A n
|
1 .
r = −∞
Hence, for any integer n
2 the cardinal B-spline basis B =
{
N n ( x
r )
}
,r
Z is a Riesz basis of V 0
with bounds A = A n and B =1.
Example: Compute the optimal Riesz bounds for the first and second order
cardinal B-splines, N ! and N 2 . From equation (8.18), we have
| N 1 (2 x +2 πr )
sin 2 x
1!
2 =
d
dx cot x,
|
r = −∞
sin 2 x (
cosec 2 x ) ,
=
=1 ,
or,
| N 1 ( ω +2 πr )
2 =1 ,
|
r =
−∞
and,
| N 2 (2 x +2 πr )
sin 4 x
3!
d 3
2 =
|
dx 3 cot x,
r = −∞
sin 4 x
6
2( cosec 4 x +2 cosec x cot x )
=
{−
}
,
2
6 (1 + 2 cos 2 x ) ,
=
1
3 (1 + 2 cos 2 x ) ,
=
or,
3 cos 2 ( ω
2 = 1
3 + 2
| N 2 ( ω +2 πr )
|
2 ) .
r =
−∞
{
N 1 ( .
r )
}
Hence,
is orthonormal and
1
3
| N 2 ( ω +2 πr )
2
|
1 .
r = −∞
8.2.2 Scaling and Cardinal B-Spline Functions
Since the cardinal B-spline basis B is a Riesz basis of V 0 , one can conclude
that
2 j/ 2 N n (2 j x
{
r ) ,r
Z
}
(8.19)
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