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∞
n−
1
2
λ
r
cos
ω
+
λ
r
|
1
1
−
| N
n
(
ω
+2
πr
)
2
=
|
,
(2
n
−
1!)
λ
r
|
r
=
−∞
r
=1
since
λ
r
s are negative and
−
1
≤
cos
ω
≤
1wehave,
∞
| N
n
(
ω
+2
πr
)
2
A
n
≤
|
≤
1
.
r
=
−∞
Hence, for any integer
n
≥
2 the cardinal B-spline basis
B
=
{
N
n
(
x
−
r
)
}
,r
∈
Z
is a Riesz basis of
V
0
with bounds
A
=
A
n
and
B
=1.
Example: Compute the optimal Riesz bounds for the first and second order
cardinal B-splines,
N
!
and
N
2
. From equation (8.18), we have
∞
| N
1
(2
x
+2
πr
)
sin
2
x
1!
2
=
d
dx
cot
x,
|
−
r
=
−∞
sin
2
x
(
cosec
2
x
)
,
=
−
−
=1
,
or,
∞
| N
1
(
ω
+2
πr
)
2
=1
,
|
r
=
−∞
and,
∞
| N
2
(2
x
+2
πr
)
sin
4
x
3!
d
3
2
=
|
−
dx
3
cot
x,
r
=
−∞
sin
4
x
6
2(
cosec
4
x
+2
cosec
x
cot
x
)
=
−
{−
}
,
2
6
(1 + 2 cos
2
x
)
,
=
1
3
(1 + 2 cos
2
x
)
,
=
or,
∞
3
cos
2
(
ω
2
=
1
3
+
2
| N
2
(
ω
+2
πr
)
|
2
)
.
r
=
−∞
{
N
1
(
.
−
r
)
}
Hence,
is orthonormal and
∞
1
3
≤
| N
2
(
ω
+2
πr
)
2
|
≤
1
.
r
=
−∞
8.2.2 Scaling and Cardinal B-Spline Functions
Since the cardinal B-spline basis
B
is a Riesz basis of
V
0
, one can conclude
that
2
j/
2
N
n
(2
j
x
{
−
r
)
,r
∈
Z
}
(8.19)
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