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n
d
j
=
α
i,k
(
j
)
P
i
(7.7)
i
=1
for some
α
i,k
(
j
). Consider two different cases for understanding.
Case 1:
k
= 1 (step-functions)
In this case,
n
f
(
x
)=
B
i,
1
(
x
)
P
i
,
(7.8)
i
=1
where
B
i,
1
=1
,
τ
i
≤
x<τ
i
+1
,
=0
,
otherwise.
If
m
f
(
x
)=
N
j,
1
(
x
)
d
j
,
(7.9)
j
=1
where
N
j,
1
=1
,
t
j
≤
x<t
i
+1
,
(7.10)
=0
,
otherwise,
then
d
j
=
P
i
,
τ
i
≤
t
j
<τ
i
+1
.
Therefore, in equation (7.7) we must have,
α
i,
1
(
j
)=1
,
τ
i
≤
t
j
<τ
i
+1
,
=0
,
otherwise.
Hence, one can easily note that
α
i,
1
(
j
)=
B
i,
1
(
t
j
)
Case 2:
k
= 2 (piecewise linear functions)
For this case, we can consider
n
f
(
x
)=
B
i,
2
(
x
)
P
i
,
(7.11)
i
=1
where
B
i,
2
(
x
)=(
x
−
τ
i
)
/
(
τ
i
+1
−
τ
i
)
,
τ
i
≤
x<τ
i
+1
,
=(
τ
i
+2
−
x
)
/
(
τ
i
+2
−
τ
i
+1
)
,
i
+1
≤
x<τ
i
+2
,
=0
,
otherwise.
Now suppose
m
f
(
x
)=
N
j,
2
(
x
)
d
j
,
(7.12)
j
=1
where
N
j,
2
(
x
)=(
x
−
t
j
)
/
(
t
j
+1
−
t
j
)
,
t
j
≤
x<t
i
+1
,
=(
t
j
+2
−
x
)
/
(
t
j
+2
−
t
j
+1
)
,
j
+1
≤
x<t
i
+2
,
=0
,
otherwise.
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