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w
1 ( β 1 2 ,t )=(6 β 1 [ t 2
2 t +1]+ β 1 t [ t
1]
(6.29)
+ β 1 [ t 2
1] + β 2 t [ t
1])
w 0 ( β 1 2 ,t )=6( β 1 t (
t 2 +1]
t +2)+ β 1 [
(6.30)
t 2 )
+ β 2 t [
t +1]
w 1 ( β 1 2 ,t )=6 t 2 /δ.
(6.31)
Therefore,
P i ( t )=(
6 β 1 (1
t 2 )) V i− 2
+(6 β 1 [ t 2
2 t +1]+ β 1 t [ t
1]
+ β 1 [ t 2
1] + β 2 t [ t
1]) V i− 1
(6.32)
+6( β 1 t (
t 2 +1]
t +2)+ β 1 [
t 2 ) V 0
+ β 2 t [
t +1]
+6 t 2 V i +1 /δ.
The second derivative of the curve P i ( t ) can be computed through
w
2 ( β 1 2 ,t )=12 β 1 (1
t )
(6.33)
w
1 ( β 1 2 ,t ) = 6(2 β 1 [ t
1] + 2 β 1 [ t
1]
(6.34)
+2 β 1 t + β 2 [2 t
1])
w 0 ( β 1 2 ,t ) = 6(2 β 1 (
t +1)
2 β 1 t
(6.35)
+ β 2 [
2 t +1]
2 t )
w 1 ( β 1 2 ,t )=12 t/δ.
(6.36)
This yields,
P i ( t ) = (12 β 1 (1
t )) V i− 2
+ 6(2 β 1 [ t
1] + 2 β 1 [ t
1]
+2 β 1 t + β 2 [2 t
1]) V i− 1
(6.37)
+ 6(2 β 1 (
t +1)
2 β 1 t
+ β 2 [
2 t +1]
2 t ) V 0
+12 tV i +1 /δ.
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