Chemistry Reference
In-Depth Information
Knowing the diagonal elements of the induction matrix, we can now calculate
the frequency of a given Γ irrep of the main group, using the character theorem:
χ Γ (g) Tr D
G (g)
1
| G |
H
c Γ (γH
G)
=
G ¯
g
g G ¯
χ Γ (g)
κ
P κκ (g)χ γ g 1
gg κ
1
=
(4.78)
κ
|
G
|
The only elements
g that are allowed in the summation over κ are the ones such
ˆ
H A . For other elements, P κκ (g) are zero. Let us denote by h the
subelement that allows us to express
g κ ˆ
that (
ˆ
g
g κ )
ˆ
ˆ
g as
g κ h
g 1
κ
g
ˆ
ˆ
(4.79)
Introducing this substitution in Eq. ( 4.78 ) yields
κ χ Γ g κ hg κ χ γ (h)P κκ g κ hg κ
1
c Γ (γH G) =
(4.80)
|
G
|
h
H
The first character in this equation belongs to the full group and is the same for all
elements of a conjugacy class, and hence,
χ Γ g κ hg κ =
χ Γ (h)
(4.81)
Substituting the result of Eq. ( 4.81 ) and the sum rule in Eq. ( 4.75 ) into the character
expression finally gives
κ ¯
χ Γ (h)χ γ (h)P κκ g κ hg κ
1
c Γ (γH
G)
=
|
G
|
h H
χ Γ (h)χ γ (h)
κ
P κκ g κ hg κ
h H ¯
1
=
|
G
|
1
| H |
H χ Γ (h)χ γ (h)
=
h
=
c γ (Γ G
H)
(4.82)
which concludes the proof. Armed with the subduction tables, we can now read
these at once in the opposite sense and obtain the corresponding induction frequen-
cies. As a simple example, consider a hydrogen atom in ammonia. The site symme-
try is C s , and the subduction from C 3 v reads:
A 1
a
A 2
b
(4.83)
E
a
+
b
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