Chemistry Reference
In-Depth Information
Knowing the diagonal elements of the induction matrix, we can now calculate
the frequency of a given
Γ
irrep of the main group, using the character theorem:
χ
Γ
(g)
Tr
D
G
(g)
1
|
G
|
H
↑
c
Γ
(γH
↑
G)
=
G
¯
g
∈
g
∈
G
¯
χ
Γ
(g)
κ
P
κκ
(g)χ
γ
g
−
1
gg
κ
1
=
(4.78)
κ
|
G
|
The only elements
g
that are allowed in the summation over
κ
are the ones such
ˆ
H
A
. For other elements,
P
κκ
(g)
are zero. Let us denote by
h
the
subelement that allows us to express
g
−
κ
ˆ
that
(
ˆ
g
g
κ
)
ˆ
∈
ˆ
g
as
g
κ
h
g
−
1
κ
g
ˆ
=ˆ
ˆ
(4.79)
Introducing this substitution in Eq. (
4.78
) yields
κ
χ
Γ
g
κ
hg
−
κ
χ
γ
(h)P
κκ
g
κ
hg
−
κ
1
c
Γ
(γH
↑
G)
=
(4.80)
|
G
|
h
∈
H
The first character in this equation belongs to the full group and is the same for all
elements of a conjugacy class, and hence,
χ
Γ
g
κ
hg
−
κ
=
χ
Γ
(h)
(4.81)
Substituting the result of Eq. (
4.81
) and the sum rule in Eq. (
4.75
) into the character
expression finally gives
κ
¯
χ
Γ
(h)χ
γ
(h)P
κκ
g
κ
hg
−
κ
1
c
Γ
(γH
↑
G)
=
|
G
|
h
∈
H
χ
Γ
(h)χ
γ
(h)
κ
P
κκ
g
κ
hg
−
κ
h
∈
H
¯
1
=
|
G
|
1
|
H
|
H
χ
Γ
(h)χ
γ
(h)
=
h
∈
=
c
γ
(Γ G
↓
H)
(4.82)
which concludes the proof. Armed with the subduction tables, we can now read
these at once in the opposite sense and obtain the corresponding induction frequen-
cies. As a simple example, consider a hydrogen atom in ammonia. The site symme-
try is
C
s
, and the subduction from
C
3
v
reads:
A
1
→
a
A
2
→
b
(4.83)
E
→
a
+
b