Chemistry Reference
In-Depth Information
Fig. 1.3
The rotation of the
function
f(x,y)
counterclockwise by an angle
α
generates a new function,
f
(x,y)
. The value of the
new function at
P
2
is equal to
the value of the old function
at
P
1
. Similarly, to find the
value of the new function at
P
1
,wehavetoretrievethe
value of the old function at a
point
P
0
, which is the point
that will be reached by the
clockwise rotation of
P
1
in Fig.
1.3
. In order to determine the mathematical form of the new transformed
function, we must be able to compare the value of the new function with the origi-
nal function
at the same point
, i.e., we must be able to see how the property changes
at a given point. Thus, we would like to know what would be the value of
Rf
in the
original point
P
1
. Equation (
1.8
) cannot be used to determine this since the trans-
formed function is as yet unknown and we thus do not know the rules for working
out the brackets in the left-hand side of the equation. However, this relationship
must be true for every point; thus, we may substitute
R
−
1
P
1
for
P
1
on both the left-
and right-hand sides of Eq. (
1.8
). The equation thus becomes
Rf
R
R
−
1
P
1
=
Rf( EP
1
)
f
R
−
1
P
1
=
Rf(P
1
)
=
(1.9)
This result reads as follows: the transformed function attributes to the original point
P
1
the property that the original function attributed to the point
R
−
1
P
1
.InFig.
1.3
this point from which the function value was retrieved is indicated as
P
0
. Thus, the
function and the coordinates transform in opposite ways.
2
This connection transfers
the operation from the function to the coordinates, and, since the original function
is a known function, we can also use the toolbox of corresponding rules to work out
the bracket on the right-hand side of Eq. (
1.9
).
As an example, consider the familiar 2
p
orbitals in the
xy
plane: 2
p
x
,
2
p
y
. These
orbitals are usually represented by the iconic dumbell structure.
3
We can easily
find out what happens to these upon rotation, simply by inspection of Fig.
1.4
,in
which we performed the rotation of the 2
p
x
orbital by an angle
α
around the
z
-axis.
Clearly, when the orbital rotates, the overlap with the 2
p
x
function decreases, and
the 2
p
y
orbital gradually appears. Now let us apply the formula to determine
R
2
p
x
.
The functional form of the 2
p
x
orbital for a hydrogen atom, in polar coordinates,
reads:
R
2
p
(r)Θ
2
p
|
1
|
(θ)Φ
x
(φ)
, where
R
2
p
(r)
is the radial part,
Θ
2
p
|
1
|
(θ)
is the part
2
A more general expression for the transportation of a quantum state may also involve an additional
phase factor, which depends on the path. See, e.g., [
1
].
3
The electron distribution corresponding to the square of these orbitals is described by a lemniscate
of Bernoulli. The angular parts of the orbitals themselves are describable by osculating spheres.