Civil Engineering Reference
In-Depth Information
(
f
1
=15
:
15
δ
0
1
+1
:
314
f
3
= 476
:
19
δ
0
3
+3
ð6
:
60Þ
Therefore, Eq. (6.59) becomes:
2500
−
6500 0
2500
0.03
F
−
6500 43900
4500
−
6500
x
0
6
=
ð6
:
61Þ
0
4500
750 15.15 0
+
−δ
′′
1.314
1
′′
2500
−
6500 0
2500 476.19
+
−δ
3
3
Solving for Eq. (6.39) gives:
<
=
<
=
x
6
δ
0
1
δ
0
3
F
w
0
:
0093 rad
0
:
0528 m
0
:
0039 m
4
:
8717 MN
=
ð6
:
62Þ
:
;
:
;
(a)
0.0073
0.004
0.004
0.0073
0.0093
0.0
3
l
l
l
l
0.052
8
0
.0039
(b)
0.6589
0.5463
0.2055
0.2055
0.5463 0.6689
0.6589
0.7518
0.7518
0.6589
4.8717
-2.111
2.111
1.25
0.95
0.95
1.25
Figure 6.10
Graphical
illustration of
the response of
the RC frame-shear wall structure.
(a)
Deformations; (b) Internal forces.
