Development of Analytical and Preparatory Techniques - Chlorophyll Biosynthesis and Technological Applications - page 87

and standard deviation (Sx 3 ) ranged from 0.3 % 0.1 % for pure solutions of Chl

b to 3.9 % for mixtures containing 6 % of Chl b .

Based on the results of Table 3.4 , it is there forem recommended that for precise
calculations with Eq. ( 3.35 ), the proper values for X 3 and Sx 3 should be calculated
by interpolation from Table 3.4 . For less rigorous calculations an overall average
value of

38.9 %

18.1 % for X 3

2.2 % for Sx 3 may be utilized.

3.4.4 Calculation of Pheo(phorbide) b

3.4.4.1 Calculation of Pheophytin and Pheophorbide
b [Pheo(phorbide)b] in Various Pigment Mixtures

The equation for calculating pheo(phorbide) b (F660 E4381] was derived from the
following simultaneous equations:

ð F660 E438 Þ¼ Chl ð ide Þ a ð F660 E4438 Þþ Pheo ð bide Þ a ð F660 E438 Þ

þ Chl ð ide Þ b ð F660E438 Þþ Pheo ð bide Þ b ð F660 E438 Þ

ð F660 E460 Þ¼þ k 37 Chl ð ide Þ a ð F660 E438 Þþ k 38 Pheo ð bide Þ a ð F660 E438 Þ

þ k 39 Chl ð ide Þ b ð F660 E438 Þþ k 40 Pheo ð bide Þ b ð F660 E438 Þ

F674 E433 Þ¼ k 41 Chl ð ide Þ a ð F660 E438 Þþ k 42 Pheo ð bide Þ a ð F660 E438 Þ

þ k 43 Chl ð ide Þ b ð F660 E438 Þþ k 44 Pheo ð bide Þ b ð F660 E438 Þ

F674 E412 Þ¼þ k 45 Chl ð ide Þ a ð F660 E438 Þþ k 46 Pheo ð bide Þ a ð F660 E438 Þ

þ k 47 Chl ð ide Þ b ð F660 E438 Þþ k 48 Pheo ð bide Þ b ð F660 E438 Þ

Where

K 37 ¼ Chl ð ide Þ a ð F660 E460 Þ= Chl ð ide Þ a ð F660 E438 Þ

K 38 ¼ Pheo ð bide Þ a ð F660 E460 Þ= Pheo ð bide Þ a ð F660 E438 Þ

K 39 ¼ Chl ð ide Þ b ð F660 E460 Þ= Chl ð ide Þ b ð F660 E438 Þ

K 40 ¼ ð Þ ð Þ= ð Þ ð Þ

Pheo bide b F660 E460 Pheo bide b F660 E438

K 41 ¼ Chl ð ide Þ a ð F674 E433 Þ= Chl ð ide Þ a ð F660 E438 Þ

K 42 ¼ Pheo ð bide Þ a ð F674 E433 Þ= Pheo ð bide Þ a ð F660 E4438 Þ

K 43 ¼ Chl ð ide Þ b ð F674 E433 Þ= Chl ð ide Þ b ð F660 E438

K 44 ¼ Pheo ð bide Þ b ð F674 E412 Þ= Pheo ð bide Þ b ð F660 E438 Þ

K 45 ¼ Chl ð ide Þ a ð F674 E412 Þ= Chl ð ide Þ a ð F660 E438 Þ

K 46 ¼ Pheo ð bide Þ a ð F674 E412 Þ= Pheo ð bide Þ a ð F660 E438 Þ

K 47 ¼ Chl ð ide Þ b ð F674 E412 Þ= Chl ð ide Þ b ð F660 E438 Þ

K 48 ¼ Pheo ð bide Þ b ð F674 E412 Þ= Pheo ð bide Þ b ð F660 E438 Þ