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Clearly, γv is the trace of v on the boundary, i.e., the restriction of v to the
boundary. We know that the evaluation of an H 1 function at a single point does not
always make sense. Theorem 3.1 asserts that the restriction of v to the boundary
is at least an L 2 function.
We delay the proof of the trace theorem until the end this section.
Boundary-Value Problems with Natural Boundary Conditions
3.2 Theorem. Suppose the domain satisfies the hypotheses of the trace theorem.
Then the variational problem
1
2 a(v, v)
J(v) :
=
(f, v) 0 ,
(g, v) 0 , −→
min !
has exactly one solution u H 1 (). The solution of the variational problem lies in
C 2 () C 1 ( ¯ ) if and only if there exists a classical solution of the boundary-value
problem
Lu = f
in ,
( 3 . 4 )
ν i a ik k u = g
on ,
i,k
in which case the two solutions are identical. Here ν :
= ν(x) is the outward-
pointing normal defined almost everywhere on .
Proof. Since a is an H 1 -elliptic bilinear form, the existence of a unique mini-
mum u H 1 () follows from the Lax-Milgram Theorem. In particular, u is
characterized by
for all v H 1 ().
a(u, v) = (f, v) 0 , + (g, v) 0 ,
( 3 . 5 )
Now suppose (3.5) is satisfied for u C 2 () C 1 ( ¯ ) .For v H 0 () ,
γv =
0, and we deduce from (3.5) that
for all v H 0 ().
a(u, v) = (f, v) 0
By (2.21), u is also a solution of the Dirichlet problem, where we define the
boundary condition using u . Thus, in the interior we have
Lu
=
f
in .
( 3 . 6 )
For v H 1 () , Green's formula (2.9) yields
v∂ i (a ik k u) dx =−
i va ik k udx +
va ik k i ds.
 
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