Civil Engineering Reference
In-Depth Information
5.4 Lemma. The mapping
0
div : RT 0 M
is surjective.
Proof. After enlarging by finitely many triangles if necessary, we may assume
that is convex. Given f M
0 , there is a u H 2 () H 0 () such that
u = f . Set q :
=
grad u . By Gauss' integral formula we have
q · nds =
div qdx =
fdx.
∂T
T
T
From (5.9a) we conclude that T div ρ qdx = ∂T q) · nds = T fdx. Since
div ρ q and f are constant in T , it follows that div ρ q
=
f .
0
RT 0 in the construction above is
bounded. Therefore, recalling Fortin's criterion we see that the inf-sup condition
has been established simultaneously.
The error of the finite element solution will be derived from the approximation
error.
Finally we note that the mapping M
5.5 Lemma. Let T h be a shape-regular triangulation of . Then
q ρ q H( div ,) ch | q | 1 +
inf
v h M
0
div q v h 0 .
Proof. We first consider the interpolation on a triangle. By the trace theorem the
functional q e q · nds , e ∂T , is continuous on H 1 (T ) 2 . Moreover, we have
ρ T q = q for q P
2
2
0
0 since
P
RT 0 . Therefore, the Bramble-Hilbert lemma and
a scaling argument yield
q ρ q 0 ch | q | 1 .
The bound for div (q ρ q) follows from the minimal property 5.3, and the proof
is complete.
Now the error estimate of the finite element solution of (5.1)
σ σ h H( div ,) + u u h 0
c(h | σ | 1 + h u 1 +
( 5 . 13 )
0 f f h 0 )
inf
f h M
is a direct consequence of Theorem 4.5.
Moreover, there is a comparison with the standard finite element approxima-
tion.
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