Cryptography Reference
In-Depth Information
x
k
(mod
p
m
) for all
k
for all
m
≥
1. Since
x
m
≡
≥
m
, the base
p
expansions
m
must agree through the
p
m−
1
term. Therefore, the
sequence of integers
x
m
determines an expression of the form
for all
x
k
with
k
≥
∞
a
n
p
n
,
n
=0
where
m
−
1
a
n
p
n
(mod
p
m
)
x
m
≡
n
=0
for all
m
. In other words, the sequence of integers determines a
p
-adic inte-
ger. Conversely, the partial sums of a
p
-adic integer determine a sequence of
integers satisfying (A.3).
Let's use these ideas to show that
−
1 is a square in the 5-adic integers. Let
x
1
=2,so
x
1
≡−
1(mod
.
Suppose we have defined
x
m
such that
x
2
m
≡−
m
)
.
1(mod
Let
x
m
+1
=
x
m
+
b
5
m
,where
≡
−
1
− x
2
m
2
·
5
m
x
m
b
(mod 5)
.
Note that
x
2
m
≡−
1(mod5
m
) implies that the right side of this last congru-
ence is defined mod 5. A quick calculation shows that
x
2
m
+1
≡−
1(mod
m
+1
)
.
x
m
(mod 5
m
)for
Since (A.3) is satisfied, there is a 5-adic integer
x
with
x
≡
all
m
.Moreover,
x
2
m
)
≡−
1(mod
for all
m
. This implies that
x
2
=
1.
In general, this procedure leads to the following very useful result.
−
THEOREM A.2 (Hensel's Lemma)
Let f
(
X
)
be a polynomial with coe
cients that are p-adic integers and suppose
x
1
is an integer such that
f
(
x
1
)
≡
0(mod
p
)
.
If
f
(
x
1
)
≡
0(mod
p
)
,
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