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a p th power, where p is the characteristic of K , then for all but finitely many
a , these n zeros are distinct (if F is a p th power, then F
a 1 /p ) p ,
so the roots cannot be distinct; that is why this case is excluded). We say
that n isthedegreeof F .If F
a =( F 1 /p
a has n distinct zeros for each a and F has
n distinct poles, then we say that F is unramified.
PROPOSITION 12.18 (Riemann-Hurwitz)
Let C 1 , C 2 be curves of genus g 1 ,g 2 defined over an algebraicallyc osed field
K ,and let F : C 1 →C 2 be an u n ram ified rationalm ap of degree n .Then
2 g 1 2= n (2 g 2 2) .
PROOF See [49]. More generally, the Riemann-Hurwitz formula can be
extended to cover the case where F is ramified.
In our case, F is a function from the elliptic curve E , which has genus 1,
to the projective line P 1 , which has genus 0. By the above discussion, F is
unramified of degree n . Therefore, 0 =
2 n , which is a contradiction.
We conclude that e 1 ,e 2 ,e 3 must be distinct and therefore that E 2 is non-
singular. This completes the proof of Lemma 12.17.
We have shown that α :( x, y ) ( X, Y ) gives a map from E to E 2 .Equa-
tions (12.2), (12.3) show that the points in the subgroup C are exactly the
points mapping to . In particular, since maps to , Theorem 12.10
shows that α is an isogeny. Its kernel is C . By Exercise 12.8, α is separable.
This completes the proof of Theorem 12.16.
Example 12.4
Let E be given by y 2
= x 3 + ax 2 + bx ,with b =0and a 2
4 b = 0 (these
conditions make the curve nonsingular). The point (0 , 0) is a point of order 2,
so this point, along with , gives a subgroup of order 2. The set S is { (0 , 0) } .
For Q =(0 , 0), we have v Q = g Q = a 4 = b and g Q =0,so u Q = 0. Therefore,
b
x ,
by
x 2 .
X = x +
Y = y −
The curve E 2 is given by the equation
Y 2 = X 3 + aX 2
4 bX
4 ab.
Let
y 2
x 2 ,
= y x 2
X 3 = X + a = x + ax + b
x
by
x 2
− b
y
=
3 = Y = y
.
 
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