Cryptography Reference
In-Depth Information
If
z
∈
C
, recall that ord
z
f
is the order of
f
at
z
.Thatis,
z
)
ord
z
(
f
)
g
(
τ
)
,
f
(
τ
)=(
τ
−
with
g
(
z
)
=0
,∞
. We can also define the order of
f
at
i∞
. Suppose
f
(
τ
)=
a
n
q
n
+
a
n
+1
q
n
+1
+
··· ,
(9.15)
with
n
∈
Z
and
a
n
= 0, and assume that this series converges for all
q
close
to 0 (with
q
=0when
n<
0). Then
ord
i∞
(
f
)=
n.
Note that
q →
0as
τ → i∞
,soord
i∞
(
f
) expresses whether
f
vanishes (
n>
0)
or blows up (
n<
0) as
τ → i∞
.
PROPOSITION 9.16
Let
f
be a function m erom orphicin
H
su ch that
f
isnotidenticallyzeroand
su ch that
f
aτ
+
b
cτ
+
d
=
f
(
τ
)
for all
ab
∈ SL
2
(
Z
)
.
cd
Then
2
ord
i
(
f
)+
z
ord
i∞
(
f
)+
1
3
ord
ρ
(
f
)+
1
ord
z
(
f
)=0
.
=
i,ρ,i
∞
REMARK 9.17
The function
f
can be regarded as a function on the
surface obtained as follows. Identify the left and right sides on
F
to get a
tube, then fold the part with
to
a point. This gives a surface that is topologically a sphere. The proposition
expresses the fact that the number of poles of
f
equals the number of zeros on
such a surface, just as occurred for doubly periodic functions in Theorem 9.1.
The point
i
is special since a small neighborhood around
i
contains only half
of a disc inside
F
. Similarly, a small neighborhood around
ρ
includes only
1/3 of a disc from
F
(namely, 1/6 near
ρ
and 1/6 near 1 +
ρ
, which is folded
over to meet
ρ
). This explains the factors 1/2 and 1/3 in the proposition. For
a related phenomenon, see Exercise 9.3.
|
z
|
=1at
i
. Thenpinchtheopenendat
i
∞
PROOF
Let
C
be the path shown in Figure 9.4. Essentially,
C
goes around
theedgeof
F
. However, it consists of a small circular arc past each of
ρ
,1+
ρ
,
and
i
. If there is a pole or zero of
f
at a point on the path, we make a small
detour around it and a corresponding detour at the corresponding point on
the other side of
F
. The arcs near
ρ
,1+
ρ
,and
i
have radius
,where
is
chosen small enough that there are no zeros or poles of
f
inside the circles,
except possibly at
ρ
,1+
ρ
,or
i
. Similarly, the top part of
C
is chosen to have
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