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for some constant
C
. Taking logs yields
h
(
P
+
Q
)+
h
(
P − Q
)
≤
2
h
(
P
)+2
h
(
Q
)+
c
(8.9)
for some constant
c
.
We now need to prove the inequality in (8.6). First we'll prove an inequality
between
h
(
R
)and
h
(2
R
)forpoints
R
.
LEMMA 8.22
Let
R ∈ E
(
Q
)
.Thereexistsaconstant
C
2
,independent of
R
,such that
4
h
(
R
)
≤
h
(2
R
)+
C
2
.
PROOF
Let
R
=(
a
b
,y
)
with
y
∈
Q
and
a, b
∈
Z
with gcd(
a, b
)=1. Let
h
1
=
a
4
−
8
Bab
3
+
A
2
b
4
h
2
=(4
b
)(
a
3
+
Aab
2
+
Bb
3
)
Δ=4
A
3
+27
B
2
.
−
2
Aa
2
b
2
By Lemma 3.8, there exist homogeneous polynomials
r
1
,r
2
,s
1
,s
2
∈
Z
[
a, b
]of
degree 3 (the coecients depend on
A, B
) such that
4Δ
b
7
=
r
1
h
1
+
r
2
h
2
(8.10)
4Δ
a
7
=
s
1
h
1
+
s
2
h
2
.
(8.11)
For a homogeneous polynomial
p
(
x, y
)=
c
0
x
3
+
c
1
x
2
y
+
c
2
xy
2
+
c
3
y
3
,
we have
)
3
.
|
p
(
a, b
)
|≤
(
|
c
0
|
+
|
c
1
|
+
|
c
2
|
+
|
c
3
|
)Max(
|
a
|
,
|
b
|
Suppose
|
b
|≥|
a
|
. It follows that
7
|
4Δ
||
b
|
≤|
r
1
(
a, b
)
||
h
1
|
+
|
r
2
(
a, b
)
||
h
2
|
3
Max(
|h
1
|, |h
2
|
)
,
≤ C
1
|b|
for some constant
C
1
independent of
R
. Therefore,
4
|
4Δ
||b|
≤ C
1
Max(
|h
1
|, |h
2
|
)
.
Let
d
=gcd(
h
1
,h
2
). Then (8.10) and (8.11) imply that
d |
4Δ
b
7
and
d |
4Δ
a
7
.
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