Cryptography Reference
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is therefore the tangent line at this point, and the slope is computed by implicit
differentiation of
s
=
t
3
+
Ats
2
+
Bs
3
:
ds
dt
=3
t
2
+
As
2
+2
Ast
ds
dt
+3
Bs
2
ds
dt
.
Solving for
ds/dt
yields the expression in the statement of the lemma when
t
1
=
t
2
=
t
and
s
1
=
s
2
=
s
.
Since
s
1
≡
s
2
≡
0(mod
p
), we find that the denominator
B
(
s
2
+
s
1
s
2
+
s
1
)
1
−
A
(
s
1
+
s
2
)
t
1
−
≡
1(mod
p
)
.
Since
p
r
|t
i
,wehave
t
2
+
t
1
t
2
+
t
1
+
As
2
≡
0(mod
p
2
r
)
.
Therefore,
α ≡
0(mod
p
2
r
). Since
p
3
r
|s
i
,wehave
β
=
s
i
− αt
i
≡
0(mod
p
3
r
)
.
The point
P
3
is the third point of intersection of the line
s
=
αt
+
β
with
s
=
t
3
+
As
2
t
+
Bs
3
. Therefore, we need to solve for
t
:
αt
+
β
=
t
3
+
A
(
αt
+
β
)
2
t
+
B
(
αt
+
β
)
3
.
This can be rearranged to obtain
0=
t
3
+
2
Aαβ
+3
Bα
2
β
1+
Bα
3
+
Aα
2
t
2
+
··· .
The sum of the three roots is the negative of the coe
cient of
t
2
,so
2
Aαβ
+3
Bα
2
β
1+
Bα
3
+
Aα
2
t
1
+
t
2
+
t
3
=
−
0(mod
p
5
r
)
.
≡
The last congruence holds because
p
2
r
α
and
p
3
r
0
(mod
p
r
), we have
t
3
≡
0(mod
p
r
). Therefore,
s
3
=
αt
3
+
β ≡
0(mod
p
3
r
).
By Lemma 8.3,
P
3
∈ E
r
.Moreover,
|
|
β
.Sin e
t
1
≡
t
2
≡
λ
r
(
P
1
)+
λ
r
(
P
2
)+
λ
r
(
P
3
)
≡ p
−r
(
t
1
+
t
2
+
t
3
)
≡
0(mod
p
4
r
)
.
Therefore,
λ
r
is a homomorphism. This completes the proof of Theorem 8.1.
COROLLARY 8.6
Letthe notationsbeasin T heorem 8.1. If
n>
1
and
n
is not a pow er of
p
,
then
E
1
con tains no points of exact order
n
.(Seealso T heorem 8.9.)
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