Cryptography Reference
In-Depth Information
Figure 3.6
PROPOSITION 14 Suppose a 1 , a 2 , . . . , a n are positive integers, and p is a prime which
divides a 1 a 2 ... a n . Then there is an integer i such that 1 i n and p | a i .
Proof. If n = 1, the result is trivially true. Now suppose the theorem is true for n = k , and
consider a product of k + 1 integers a 1 a 2 ... a k 1 divisible by p . Since p | a 1 a 2 ... a k 1 = ( a 1 a 2
... a k ) a k 1 , proposition 13 says either p | a 1 a 2 ... a k , or p | a k 1 . If p | a k 1 , we are finished. If,
on the other hand p | a 1 a 2 ... a k , our supposition says an integer i between 1 and n (inclu-
sive) such that p | a i . In this case, induction establishes the desired result.
PROPOSITION 15 (The Fundamental Theorem of Arithmetic.) Every positive integer
n
greater than 1 can be written in the form
n
=
p 1 p 2 ...
p r
where each
p r
is prime,
i
= 1,
2, . . . ,
n
. Furthermore, this representation is unique.
Proof.
Assume some positive integer greater than 1 cannot be written as a product of
primes, and let
n
n
be the smallest such integer. If
is prime, it is trivially a product of primes.
n
ab
a
n
b
n
n
So
=
is composite, where 1 <
<
, 1 <
<
. Since
is the smallest number greater
a
b
than 1 which cannot be written as a product of primes,
and
must both be products of
n
ab
n
primes. But since
is also a product of primes, contrary to our assumption. Given
that this prime factorization of
=
,
n
n
exists, we must now show it is unique. Suppose
has two
different factorizations
n
=
p 1 p 2 ...
p m =
q 1 q 2 ...
q k
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