Biomedical Engineering Reference
In-Depth Information
To find the exact solution, we need boundary conditions for the particular flow scenario. Due
to the no-slip boundary condition, we know that the velocity at both walls is zero and that the
shear stress at the centerline is zero. Therefore, our boundary conditions are
u
ð
0
Þ
5
0
u
ð
h
Þ
5
0
du
ð
h
=
Þ
2
5
0
dy
Using two of these conditions to solve for the integration constants,
0
2
2
@
p
u
ð
0
Þ
5
x
1
c
1
0
1
c
2
5
0
μ
@
c
2
5
0
du
ð
h
=
2
Þ
h
=
2
μ
@
p
c
1
5
x
1
dy
@
h
2
@
p
c
1
52
μ
@
x
Substituting the values for these integration constants into the velocity equation,
y
2
2
@
p
h
2
@
p
1
2
@
p
y
2
u
ð
y
Þ
5
x
y
x
ð
hy
Þ
x
2
5
2
μ
@
μ
@
μ
@
For this particular flow scenario,
μ
5
3
:
5cP
@
p
40 mmHg
2
50 mmHg
2 mmHg
=
cm
x
5
52
@
5cm
0cm
2
h
5
500
μ
m
1
3
:
81
Þ
5
2
y
2
y
2
u
ð
y
Þ
5
5cP
ð
2
2 mmHg
=
cm
Þð
500
μ
my
ms
ð
500
μ
my
Þ
2
2
2
3
:
μ
The shear stress profile for this particular flow is equal to
@
u
y
1
@
v
5
μ
@
u
τ
xy
5
μ
@
@
x
@
y
y
μ
@
p
h
2
@
p
5
@
p
h
2
τ
xy
5
μ
y
x
2
2
@
μ
@
x
@
x
Substituting the appropriate known values for this particular scenario,
y
μ
@
p
h
2
@
p
5
@
p
h
2
τ
xy
5
μ
x
2
y
2
@
μ
@
x
@
x
dyne
cm
2
0
:
267
m
ð
y
250
μ
m
Þ
52
2
μ
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