Biomedical Engineering Reference
In-Depth Information
Suppose that
l x = 2[m],
l y = 1[m], H P = 20[N],
V P = 10[N].
Substitution of these values into the equation above, renders:
20
H A
H B =
0
10
+
V B =
0
2 H B
20
20
=
0.
Clearly, from the second equation it follows immediately that V B
=−
10 [N],
while from the last equation it is clear that H B =−
20 [N], which leaves the first
equation to calculate H A as H A =
0 [N]. Hence we have the solution:
H A =
0[N], H B =−
20 [N],
V B =−
10 [N].
Example 3.4 An example of a statically indeterminate case appears if the rolling support at
point A of Fig. 3.4 is replaced by a hinge as in point B. In that case an additional
reaction force in the vertical direction must be introduced at point A, see Fig. 3.6 .
With the same values of the parameters as before, force and moment equilibrium
yields
20
H A
H B =
0
10
+
V A +
V B =
0
2 H B
20
20
=
0.
V A
V A
A
H A
H A
V P
l y
V B
V B
P
H P
l y
H B
H B
B
l x
y
x
Figure 3.6
Free body diagram of the simple loaded body, statically indeterminate case.
 
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