Biomedical Engineering Reference
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and
0 · σ + ρ 0 q = 0.
(13.12)
The equation of motion is reduced to the equilibrium equation. Only boundary
conditions are necessary to solve this set. Initial conditions are no longer appli-
cable. In every point of the outer surface of V 0 three (scalar) relations have to be
specified. In this context, to find a unique solution for the displacement field, it is
necessary to suppress movement of the configuration as a rigid body. This will be
further elucidated in the following example.
Example 13.1 Consider a homogeneous body with reference volume V 0 under a given hydro-
static pressure p . For the stress field in V 0 satisfying the (dynamic) boundary
conditions and the equilibrium equations, it can be written:
σ
(
x 0 )
=−
p I for all
x 0 in V 0 .
For the strain field, according to Hooke's law it is found:
p
3 K I for all
ε
x 0 )
=−
x 0 in V 0 .
(
A matching displacement field is, for example,
p
3 K x 0 .
It is easy to verify that the above given solution satisfies all equations. However,
because in the given problem description the displacement as a rigid body is not
prescribed the solution is not unique. It can be proven that the general solution for
the components of the displacement vector reads:
u ( x 0 ) =−
p
3 K x 0 + c 1 c 6 y 0 + c 5 z 0
u y =−
u x =−
p
3 K y 0 +
c 2 +
c 6 x 0
c 4 z 0
p
3 K z 0 + c 3 c 5 x 0 + c 4 y 0 ,
with c i ( i = 1, 2, ... 6) yet undetermined constants. The constants c 1 , c 2 and c 3
represent translations in the coordinate directions and the constants c 4 , c 5 and c 6
(small) rotations around the coordinate axes.
u z =−
13.2.5 Linear plane stress theory, static
Consider a flat membrane with, in the reference configuration, constant thickness
h . The 'midplane' of the membrane coincides with the x 0 y 0 -plane, while in the
 
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