Civil Engineering Reference
In-Depth Information
K
s
Relative density of soil
Pile material
δ
Loose
Dense
Steel
20°
0.5
1.0
Concrete
1.0
2.0
0.75
φ
′
Timber
1.5
4.0
0.67
φ
′
where
K
s
=
the coefficient of lateral earth pressure
′
σ
v
=
average effective overburden pressure acting along the embedded length of the pile shaft
δ
=
angle of friction between the pile and the soil.
Hence
′
Q
=
A K
σ
v
tan
δ
s
s
s
and
=
′
′
Q
σ
N A
+
A K
σ
v
tan
δ
u
v
q
b
s
s
′
σ
v
N
does not increase indefinitely but has a limiting
value at a depth of some 20 times the pile diameter. There is therefore a maximum value of
′
σ
v
N
that can
be used in the calculations for Q
b
.
In a similar manner there is a limiting value that can be used for the average ultimate skin friction, f
s
.
This maximum value of f
s
occurs when the pile has an embedded length between 10 and 20 pile diameters.
Vesic (
1970)
suggested that the maximum value of the average ultimate skin resistance should be obtained
from the formula:
4
f
s
=
0 08 10
1 5
.
(
)
.
(
Dr
)
where D
r
=
the relative density of the cohesionless soil.
In practice if
s
is often taken as 100 kPa if the formula gives a greater value.
Unlike piles embedded in cohesive soils, the end resistances of piles in cohesionless soils are of con-
siderable significance and short piles are therefore more efficient in cohesionless soils.
Example 10.1:
Undrained analysis
A pile of diameter 400 mm and length 6 m is to be installed into a deep deposit of clay.
The clay has an undrained shear strength of 180 kPa at a depth of 6 m and an average
undrained shear strength of 120 kPa over the depth 0-6 m.
Assuming N
c
=
9.0 and
α
=
0.6, determine the ultimate bearing capacity of the pile.