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The solution of the recurrence relation in equation (3) is shown in equation (4)
t ʲ =2 ʲ +1
ʲ
2
(4)
Substituting equation (4) in equation (2) S LU intra is obtained in equation (5)
n
uf ×
n
uf ×
(2 ʲ +1
S LU intra =
ʲ
2) =
(2
×
uf
log 2 uf
2)
(5)
Let, i curr and i next be the values of i in the current and next iterations,
Inter-iteration bit transition for LU
Inter-iteration bit transition for LUG
b a [ i curr + u 2 ] b a [ i next ]
Iteration i curr i next b a [ i curr + uf− 1] b a [ i next ]
Switching
Switching
1
0
16
32
48
64
80
96
112
16
32
48
64
80
96
112
128
0000 1111
0001 0000
5
6
5
7
0000 1000
0001 0000
2
2
3
4
5
6
7
8
0001 1111
0010 0000
0001 1000
0010 0000
3
2
4
2
3
2
5
0010 1111
0011 0000
0010 1000
0011 0000
0011 1111
0100 0000
0011 1000
0100 0000
0100 1111
0101 0000
5
0100 1000
0101 0000
0101 1111
0110 0000
6
5
8
0101 1000
0110 0000
0110 1111
0111 0000
0110 1000
0111 0000
0111 1111
1000 0000
0111 1000
1000 0000
Fig. 3. Inter-iteration switching on the address bus of data memory for first eight
iterations of LU and LUG in Fig. 2 (b) and (c), respectively, where, uf =16 and
base address ( a )=0
( Iteration ( ʷ ) ,Switching )
(1 +1)
(2 +2) , (3 +1)
(4 +3) , (5 +1) , (6 +2) , (7 +1)
(8 +4) , (9 +1) , (10 +2) , (11 +1) , (12 +3) , (13 +1) , (14 +2) , (15 +1)
···
(2 ʳ− 2 + ʳ − 2+1) , (2 ʳ− 2 +1 +1) ,···, (2 ʳ− 1
2 +2) , (2 ʳ− 1
1 +1)
(2 ʳ− 1 + ʳ − 1+1) , (2 ʳ− 1 +1 +1) ,···, (2 ʳ
2 +2) , (2 ʳ
1 +1)
(a) Inter-iteration switching after each iteration from iteration 1 to iteration 2 ʳ
1
Iteration Range
1
2 to 3
4 to 7
8 to 15
Total Switching
˃ 1 = ʲ +1
˃ 2 = ʲ +2+ ʲ +1=2 × ˃ 1 +1
˃ 3 = ʲ +3+ ʲ +1+ ʲ +2+ ʲ +1=2 × ˃ 2 +1
˃ 4 =2
=2 0
× ʲ +2 1
1
=2 1
× ʲ +2 2
1
=2 2
× ʲ +2 3
1
×
˃ 3 +1
=2 3
×
ʲ +2 4
1
···
···
···
=2 ʳ− 2
× ʲ +2 ʳ− 1
˃ ʳ− 1 =2 × ˃ ʳ− 2 +1
˃ ʳ =2 × ˃ ʳ− 1 +1
1
2 γ− 2 to 2 γ− 1
1
2 ʳ− 1 to 2 ʳ
=2 ʳ− 1
× ʲ +2 ʳ
1
1
(b) Total inter-iteration switching in mentioned iteration ranges
Fig. 4. Inter-iteration switching on the address bus of data memory for LU in Fig. 2(b),
where, base address ( a )=0
 
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