Chemistry Reference
In-Depth Information
(This is a useful thermodynamic quantity to characterize changes at constant
volume of the working substance.) For a change at constant temperature, from
Eq. (4-26)
,
dA
5
dU
2
TdS
(4-10)
Combining
Eqs. (4-25) and (4-26)
dA
5
dw
(4-11)
That is, the change in
A
in an isothermal process equals the work done on the sys-
tem by its surroundings. Conventionally, when gases and liquids are of major
interest the work done on the system is written
dw
PdV
. When we consider
elastic solids, the work done by the stress is important. If tensile force is
f
and
l
is
the initial length of the elastic specimen in the direction of the force, the work
done in creating an elongation
dl
is
52
dw5fdl
(4-12)
If a hydrostatic pressure
P
is acting in addition to the tensile force
f
, the total
work on the system is
dw
5
fdl
2
PdV
(4-13)
In the case of rubbers,
dV
is very small and if
P
5
1 atm,
PdV
is less than
10
2
3
fdl
. Thus we can neglect
PdV
and use
Eq. (4-12)
.
From
Eqs. (4-11) and (4-12)
,
ð@
A
=@
l
Þ
T
5 ð@
w
=@
l
Þ
T
5
f
(4-14)
That is, the tension is equal to the change in Helmoholtz free energy per unit
extension. From
Eqs. (4-10) and (4-12)
,
ð@
A
=@
l
Þ
T
5 ð@
U
=@
l
Þ
T
2 ð@
S
=@
l
Þ
T
5
f
(4-15)
Thus, the force consists of an internal energy component and an entropy com-
ponent [compare (iii) of
Table 4.1
for the pressure of a gas].
To evaluate
Eq. (4-15)
experimentally, we proceed in an analogous fashion to
the method used to estimate the entropy component of the pressure of a gas
(
Table 4.3
). From
Eq. (4-9)
, for any change,
dA
5
dU
2
TdS
2
SdT
(4-16)
For a reversible change, from
Eqs. (4-8) and (4-12)
,
dU 5fdl1TdS
(4-17)
Combining the last two equations,
dA
5
fdl
2
SdT
(4-18)
Thus, by partial differentiation,
ð@
A
=@
l
Þ
T
5
f