Digital Signal Processing Reference
In-Depth Information
+
c 1
c 2
c 3
c 4
E s (
H
1
2 H
H
1
2
1 H 1 )
(
1 y
=
1 H 1 )
n
(3.23)
H
H
1
2
1 H 1 )
where
n
= (
(
1 n
)
has uncorrelated elements
CN
(
0
,
1
)
. Equation ( 3.23 )
can be further rewritten as
2
+
x 1 x 2 x 3 x 4
x 2 x 5 x 6 x 7
x 3 x 6 x 8 x 9
x 4 x 7 x 9 x 10
c 1
c 2
c 3
c 4
E s
H 1 H 1 )
1
2 H 1 y
(
=
n
(3.24)
where
k 1 b
k 2 c
k 3 d
x 1 =
+
+
+
,
x 2 =
+
a
k 1 a
k 1 b
k 2 k 3 c
k 2 k 3 d
x 3 =
k 2 a
+
k 1 k 3 b
+
k 2 c
+
k 1 k 3 d
,
x 4 =
k 3 a
k 1 k 2 b
+
k 1 k 2 c
k 3 d
k 1 a
k 3 c
k 2 d
x 5 =
+
b
+
+
,
x 6 =
k 1 k 2 a
k 3 b
+
k 3 c
k 1 k 2 d
k 2 a
k 3 b
k 1 d
x 7 =
k 1 k 3 a
+
k 2 b
+
k 1 k 3 c
+
k 2 d
,
x 8 =
+
+
c
+
k 3 a
k 2 b
k 1 c
x 9 =
+
,
x 10 =
+
+
+
k 2 k 3 a
k 2 k 3 b
k 1 c
k 1 d
d
(3.25)
4
4
h 1 (
2
h 1 (
2
a
=
1 |
i
,
1
) |
,
b
=
1 |
i
,
1
) |
,
i
=
i
=
4
4
h 1 (
2
h 1 (
2
c
=
1 |
i
,
1
) |
,
d
=
1 |
i
,
1
) |
(3.26)
i
=
i
=
Now let
1
2
x 1 x 2 x 3 x 4
x 2 x 5 x 6 x 7
x 3 x 6 x 8 x 9
x 4 x 7 x 9 x 10
H
=
(3.27)
From Equation ( 3.24 ), we can see that User 1 transmits 4 different codewords along
4 different equivalent channel vectors in the 4 time slots. So the rate is 1. If k 1 , k 2 , k 3
are all real, from ( 3.27 ), it is easy to see that the equivalent channel matrix H is real.
So if QAM is used, Equation ( 3.24 ) is equivalent to the following two equations
c 1 R
c 2 R
c 3 R
c 4 R
E s H
+
H 1 Real
H
{
1 y
}=
Real
{
n
}
(3.28)
 
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