Digital Signal Processing Reference
In-Depth Information
coefficients X
[
k
]
. If we try to write the analysis DTFT formula for x
[
n
]
we
have
l g r , y i d . , © , L s
X
e j ω )=
e −j ω n
(
x
[
n
]
n
= −∞
1
N
e j 2 N nk e −j ω n
N
1
=
X
[
k
]
(4.41)
n
= −∞
k
=
0
e j 2 N nk e −j ω n
N
1
1
N
=
X
[
k
]
(4.42)
n
= −∞
k
=
0
where in (4.41) we have used the DFS reconstruction formula. Now we rec-
ognize in the last term important to recognize the last terms of (4.42) as
the DTFT of a complex exponential of frequency
(
2
π/
N
)
k ; we can therefore
write
N k
N
1
1
N
2
X ( e j ω )=
˜
X [ k ]
δ
ω
(4.43)
k
=
0
which is the relationship between the DTFT and the DFS. If we restrict our-
selves to the
interval, we can see that the DTFT of a periodic se-
quence is a series of regularly spaced deltas placed at the N roots of unity
andwhose amplitude is proportional to theDFS coefficients of the sequence.
In other words, the DTFT is uniquely determined by the DFS and vice versa .
[ π
,
π ]
Finite-Support Sequences. Given a length- N signal x
[
n
]
, n
=
0,...,
N
1andits N DFT coefficients X
[
k
]
, consider the associated finite-support
sequence
x
[
n
]
0
n
<
N
x
[
n
]=
0
other ise
from which we can easily derive the DTFT of x as
ω
N k
N
1
2
X
e j ω )=
(
X
[
k
(4.44)
k
=
0
with
N
1
1
N
e −j ω m
Λ( ω )=
m
=
0
What the above expression means, is that the DTFT of the finite support
sequence x
[
n
]
is again uniquely defined by the N DFT coefficients of the
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