Biomedical Engineering Reference
In-Depth Information
e k i t (n)
e k e (n)
tot +k i t (n)
i
P (n)
ex =
i
P peep
e k e ( t (n)
+ (n 1)
tot
) e k e (n)
i
tot
+ e (k i +k e )t (n)
+k e (n 1)
tot
(10)
(P peep P set )
i
t (n)
i
+ (n 1)
tot
+ e k e
e k i t (n)
P (n1)
P set +
i 1
:
ex
This gives iteratively dened expressions for the inspiratory and expiratory
volumes and the end-expiratory pressure.
The problem is to compute V (n)
i
(t), V (n)
(t), P (n)
for n = 1; 2; 3; ::: .
e
ex
This requires that we have a starting point for P (n)
ex , namely, P (0)
ex . This can
be done by letting P (1)
= 0 and t (0)
tot
= t tot = 60=f. Then equation (10)
ex
becomes:
e k i t (0)
i
e k i t (0 i P peep + e (k i +k e )t (0)
(P peep P set ) + e k e t (0 i P set
P (0)
ex
=
i
e k e t (0)
i 1
(11)
where t (0)
= t tot t (0)
, and t (0)
i
is any number in the interval (0; t (0)
tot ), for
e
i
example, t (0 i = 60 f .
At the end of each breath, the patient's trigger pressure P trig is com-
pared against the end expiratory pressure P ex . If P trig > P ex , then the
ventilator turns \ON" for another breath. If P trig < P ex , then the ventila-
tor stays \OFF" for one breath or more until P trig > P ex . We assume that
P trig = P peep + P sen , where P sen is the sensitivity setting of the ventilator.
In Figure 2 for illustrative purposes, we simulated our model for fteen
breaths with the following parameter values: C = 0:1 L/cmH 2 O, R i = R e =
20 cmH 2 O/L/s, P set = 22 cmH 2 O, P peep = 5 cmH 2 O, P sen = 15 cmH 2 O,
t tot = 6 s, f = 20 breaths/min, = 0:3. The ventilator sensitivity, P sen ,
in the ICU is usually between 15 cmH 2 O. At the rst breath (n = 1),
t tot
60
f = 3, we calculate thaat P ex = 12:8 and P trig = P peep + P sen =
20 > P ex = 12:8. Therefore, the ventilator is triggered. At the fourteenth
breath, P ex = 21:1 > P trig . Therefore, the ventilator fails to be triggered
and we have a prolonged expiration at the end of which we calculate that
P ex = 6:5. At the end of this long breath, P trig > P ex and P (14)
=
= 6:5,
ex
with t (14)
tot = 26 f = 6. Thus, a skipped breath has occurred at this point. In
other words, we have expiration occuring for an additional 3 seconds.
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