Image Processing Reference
In-Depth Information
Substituting Equation 7.13 in
u
11
in Equation 7.11, we have
(
)
−
1
/(
m
−
1
)
1
−
Kx v
(,)
11
u
=
11
−
1
/(
m
−
1
)
∑
c
(
)
1
Kx v
(,)
−
1
j
j
=
1
In general,
(
)
−
1
/(
m
−
1
)
1
−
Kx v
(,)
i k
u
=
(7.14)
ik
∑
c
(
)
−
1
/(
m
−
1
)
1
−
Kx v
(,)
i
j
j
=
1
To compute the cluster centre, the equation for the objective function is
⎛
⎞
n
c
⎛
2
⎞
n
⎛
c
⎞
−−
xv
2
∑
∑
∑
i
k
m
⎜
⎟
−
JUV
(,)
=
u
tanh
⎜
⎟
λ
⎜
u
−
1
⎟
( 7.1 5 )
m
ik
i
ik
2
σ
⎝
⎠
⎝
⎠
⎝
⎠
i
=
1
k
=
1
i
=
1
k
=
1
Expanding this equation and taking the first derivative with respect to
v
and
equating to zero, we obtain
n
⎛
2
⎞
−−
xv
xv
δ
δ
J
v
(
−
)
∑
i
1
m
2
i
1
=
2
u
⎜
1
−
tanh
⎟
=
0
as /tanh )
ddx
(
x
i
1
2
2
σ
σ
1
⎝
⎠
i
=
1
2
=−
1
tanh
x
(
or)
n
⎛
2
⎞
⎛
2
⎞
−−
xv
−−
xv
x
∑
i
1
i
1
m
u
⎜
1
+
tanh
⎟
⎜
1
−
tanh
⎟
(
−−=
v
1
)
0
(
or
)
i
1
i
2
2
σ
σ
⎝
⎠
⎝
⎠
i
=
1
n
⎛
2
⎞
−−
xv
Hxvxv
∑
i
1
m
u
⎜
1
+
tanh
⎟
(,)(
−=
)
0
(
or
)
i
1
i
1
i
1
2
σ
⎝
⎠
i
=
1
n
⎛
2
⎞
−−
xv
x
∑
i
1
m
uHxv
(,)
⎜
1
+
tanh
⎟
i
1
i
1
i
2
σ
⎝
⎠
i
=
1
n
⎛
2
⎞
−−
i
xv
v
∑
1
i
m
−
uHxv
(,)
⎜
1
+
tanh
⎟
=
0
1
i
1
1
2
σ
⎝
⎠
i
=
1
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