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where it is readily derived on solving the diffusion equation or in the free molecule
regime, where it is a consequence of the balance of in- and out-fluxes J D J in J out .
Here J in D a 2 v T n 1 and J out D a 2 v T n C .
To d er ive E q . 3.31 in the transition regime, let us split the distribution function
into two terms, f D f 0 C Jf J ,wheref 0 is the part of the distribution independent
of the reactant flux J and the second term is linear in J because of the linearity of the
transport equation with respect to f . We rewrite this equation in the integral form:
f D f fm C D 1 RŒf;
(3.81)
where D 1 is the inversion of the differential operator standing on the left-hand side
of the transport equation, RŒf is the collision integral, and f fm is the solution to
the collisionless transport equation with Maxwell's boundary condition. Let then
the triangle brackets < > stand for the operation that produces the flux from f ,
<f > D J. Let us apply this operator to both sides of Eq. 3.81 . On introducing
B D <D 1 Rf J > gives
J D a 2 v T .n 1 n C / C BJ
(3.82)
or
a 2 v T .n 1 n C /
1 B
J D
:
(3.83)
This is exactly Eq. 3.31 .
The efficiency ˛.a/ has dimension l 3 =t . Very simple dimension considerations
allow us to establish a general form of the condensational efficiency. Three
parameters govern the condensation kinetics: th e particle radius a ,thethermal
velocity of the condensable gas molecules v T D p 8kT=m, and their diffusivity D .
Their dimensions are a D Œcm, v T
D Œcm=s,andD D cm 2 =s . Because
˛.a/ D cm 3 =s , we can write
˛.a/ D S p a 2 v T .a v T =D/:
(3.84)
The multiplier normalizes .0/to unity, .0/ D 1 (see Eq. 3.72 ). The function
.x/is not yet known. To find this function one should solve the Boltzmann kinetic
equation that describes the time evolution of the coordinate-velocity distribution of
the condensing molecules, then find the flux of the condensing molecules toward the
particle, and then extract ˛.a/. This is not easy to do in general form. However, the
limiting situations are well analyzable (see Seinfeld and Pandis 2006 ): .x/ D 1 at
small x and .x/ D 4=x as x !1 .
It is remarkable that all existing approaches give similar dependence on the
sticking probability:
1
1 C S p F.x/
.x/ D
(3.85)
 
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