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n
det ( A )=
a ij ij ,
j =1
which is called Laplace expansion .
From this representation, if det ( A )isnotequalto0,then ij
=0for
{
a i 1 ,a i 2 ,
···
,a in }
which are not equal to 0. Thus, the following proposition
is obtained.
Proposition 1. If det ( A ) is not equal to 0 if at least one co-factor of a ij (
=0) ,
ij is not equal to 0.
It is notable that the above definition of a determinant gives the relation
between a original matrix A and submatrices (co-factors). Since cofactors gives
a square matrix of size n
1, the above proposition gives the relation between
a matrix of size n and submatrices of size n
1. In the same way, we can
discuss the relation between a corresponding matrix of size n and submatrices
of size r (1
r<n
1).
Rank and Submatrix
Let us assume that corresponding matrix and submatrix are square ( n
×
n
and r
×
r , respectively).
Theorem 2. If the rank of a corresponding matrix of size n
×
n is equal to r,
at least the determinant of one submatrix of size r
×
r is not equal to 0. That
is, there exists a submatrix A i 1 i 2 ···i r
j 1 j 2 ···j r
, which satisfies det ( A i 1 i 2 ···i r
j 1 j 2 ···j r
)
=0
Corollary 1. If the rank of a corresponding matrix of size n
n is equal to r,
all the determinants of the submatrices whose number of columns and rows
are larger than r +1(
×
n ) are equal to 0.
3 Degree of Dependence
3.1 Determinantal Divisors
From the subdeterminants of all the submatrices of size 2, all the subdeter-
minants of a corresponding matrix has the greatest common divisor, equal
to 3.
From the recursive definition of the determinants, it is show that the sub-
determinants of size r + 1 will have the greatest common divisor of the sub-
determinants of size r as a divisor. Thus,
Theorem 3. Let d k ( A ) denote the greatest common divisor of all the
subdeterminants of size k, det ( A i 1 i 2 ···i k
j 1 j 2 ···j r
,d n ( A ) are called
determinantal divisors. From the definition of Laplace expansion,
) . d 1 ( A ) ,d 2 ( A ) ,
···
d k ( A ) |d k +1 ( A ) .
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