Biomedical Engineering Reference
In-Depth Information
Energy Balance
The heats of combustion for different gas constituents are taken from Table C.2
(Appendix C). They are:
CO: 12.63 MJ/nm
3
Hydrogen: 12.74 MJ/nm
3
Methane: 39.82 MJ/nm
3
We note that 1 kg of feed produces 0.145 kmol of gas, the volumetric com-
position of which is:
CO: 27.5%
CO
2
: 3.5%
CH
4
: 2.5%
H
2
: 15%
N
2
: 51.5%
By multiplying the heating value of the appropriate constituents of the prod-
uct gas, we can find the total heating value of the product gas (the volume of
1 kmol of any gas is 22.4 nm
3
):
nm
3
ð
12
:
63
3
0
:
275
1
12
:
74
3
0
:
15
1
39
:
82
3
0
:
025
Þ
MJ
=
4nm
3
kg feed
The total energy input is equal to the heating value of the feed, which is
28.4 MJ/kg.
From
Eq. (8.40)
, the cold-gas efficiency is:
ð
3
0
:
145 kmol
=
kg feed
3
22
:
=
kmol
5
20
:
6MJ
=
20
:
6
=
28
:
4
Þ
3
100
72
:
5%
5
8.12.1.2 Hot-Gas Efficiency
Sometimes gas is burned in a furnace or boiler without being cooled, creat-
ing a greater utilization of the energy. Therefore, by taking the sensible heat
of the hot gas into account, the hot-gas efficiency,
η
hg
, can be defined as:
Q
g
M
g
1
M
g
C
p
ð
T
f
2
T
0
Þ
η
hg
5
(8.41)
LHV
f
M
f
where T
f
is the gas temperature at the gasifier exit or at the burner's entrance
and T
0
is the temperature of the fuel entering the gasifier. The hot-gas effi-
ciency assumes the heating of the unconverted char to be a loss.
Example 8.4
The gas produced by the gasifier in Example 8.3 is supplied directly to a burner
at the gasifier exit temperature, 900
C, to be burnt for cofiring in a boiler. Find
the hot-gas efficiency of the gasifier.
Solution
The product gas enters the burner at 900
C (1173K). To find the enthalpy of the
product gas, we add the enthalpies of its different components. Specific heats of
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