Civil Engineering Reference
In-Depth Information
1000)10
−6
0.0881 m
2
A
c
=
0.30 × 0.30
−
(930
+
=
α
=
200/24
=
8.33
1000)10
−6
0.1042 m
2
.
A
=
0.0881
+
8.33(930
+
=
The axial strain at transfer (Equation (2.33) ) is
1100 × 10
3
24×10
9
× 0.1042
ε
(
t
0
)
=
−
=
−
440 × 10
−6
.
The stress in concrete (Equation (2.35) ) is
σ
(
t
0
)
=
24 × 10
9
(
−
440 × 10
−6
)
=
−
10.559 MPa
(
−
1.532 ksi).
The stress in non-prestressed and in prestressed steel is
σ
ns
=
200 × 10
9
(
−
440 × 10
−6
)
=
−
88.0 MPa
(
−
12.8 ksi)
1100 × 10
3
σ
ps
=
930×10
−6
+
200 × 10
9
(
−
440 × 10
−6
)
=
1094.8 MPa
(158.8 ksi).
(b) Changes in strain and in stress due to creep, shrinkage and
relaxation
The transfo
r
med s
e
ction to be used here is composed of
A
c
+
α
(
A
ps
+
A
ns
); where
E
s
/
E
c
(
t
,
t
0
)
Using Equation (1.31)
α
=
24×10
9
E
c
=
2.4 × 0.8
=
8.215 GPa
(1192 ksi)
1
+
200
α
=
8.215
=
24.33.
The transformed area
A
=
0.0881
+
24.33(930
+
1000)10
−6
=
0.1351 m
2
.
cial force that would be necessary to prevent strain due to
creep, shrinkage and relaxation (Equations (2.41-44) ) is
The arti
fi
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