Information Technology Reference
In-Depth Information
Since users access the spectrum with the same power level and the interference
relationship and distance measurement are symmetry, we know that
P k d ʱ
kn
P k d ʱ
kn
P n d ʱ
=
=
nk .
(4.17)
p
n
p
k
p
k
n = k
k
N
n
N
n
N
Combining ( 4.16 ) and ( 4.17 ), we have that
1
2
1
2
ʦ 1 ( a )
P m d ʱ
P n d ʱ
ˉ k
ʦ 1 ( a )
=−
mk I
{ a k = a m }
nk I
{ a n = a k }
a k
p
k
p
k
m N
n N
1
2
1
2
P m d ʱ
P n d ʱ
ˉ a k
+
mk I { a k = a m } +
nk I { a n = a k } +
p
k
p
k
m N
n N
P m d ʱ
ˉ k
P m d ʱ
ˉ a k
=−
mk I
{ a k = a m }
a k +
mk I { a k = a m } +
p
k
p
k
m N
m N
ʳ k ( a )
U k ( a )
=−
+
ʳ k ( a )
=
U k ( a ) .
(4.18)
Similarly, for the part ʦ 2 , we have that
w kn
ʦ 2 ( a )
P k d ʱ
P k d ʱ
ʦ 2 ( a )
=
kn I
{ a n = a k } +
kn I { a n = a k }
sp
k
n
N
=
w kn ×
sp
k
n N
P k d ʱ
P m d ʱ
ˉ a n
kn I
{ a n = a k }
mn I { a n = a m }
m = k
p
n
m N
P k d ʱ
P m d ʱ
ˉ a n
+
kn I { a n = a k } +
mn I { a n = a m } +
p
n
m = k
m
N
w kn
+ ʳ n ( a )
ʳ n ( a )
=
sp
k
n N
w kn U n ( a )
U n ( a ) .
=
(4.19)
sp
k
n N
Finally, substituting ( 4.18 ) and ( 4.19 ) into ( 4.15 ), we obtain that
w kn U n ( a )
U n ( a ) .
ʦ ( a )
= U k ( a )
ʦ ( a )
U k ( a )
+
(4.20)
sp
k
n N
sp
k , we have that
k
Since user k can not generate interference to any user n
N
\ N
U n ( a )
sp
k .
s
= U n ( a ),
n N
k \ N
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