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1
ʸ ln
|≤ ʦ
1
ʸ ln
q a ʦ ( a )
+
|
ʩ
+
|
ʩ
|
,
a ʩ
which completes the proof.
We next discuss the efficiency of the SNE by the distributed spectrum access
algorithm when ʸ is sufficiently large (i.e., ʸ
). Let V ( a ) be the total individual
utility received by all t he users under the channel selection profile a , i.e., V ( a )
ₒ∞
=
n = 1 u n ( a ). We denote a as the NUM solution that maximizes the system-wide utility
(i.e., a
=
arg max a ʩ V ( a )) and
a as the convergent SNE by the distributed spectrum
ˆ
access algorithm (i.e.,
arg max a ʩ ʦ ( a )). We then define the perfor m ance gap
ˁ as the difference betwee n the total utility received at the NUM solution a and that
of the SNE
a
ˆ
=
a , i.e., ˁ
ˆ
=
V ( a )
V (
a ). We can show the following result.
ˆ
Theorem 4.4 The performance gap ˁ of the SNE by the distributed spectrum access
algorithm is at most
N
N
1
2
1
2
s nm ) P m d ʱ
P m d ʱ
(1
mn +
mn .
sp
n
p
n
sp
n
n = 1
n = 1
m N
m N
\ N
Proof
According to ( 4.1 ) and ( 4.5 ), we have that
N
N
N
P m d ʱ
ˉ a n
V ( a )
=
u n ( a )
=−
mn I { a n = a m }
p
n
n = 1
n = 1
n = 1
m
N
N
1
2
s nm ) P m d ʱ
=
ʦ ( a )
(1
mn I { a n = a m }
sp
n
n = 1
m
N
N
1
2
P m d ʱ
mn I { a n = a m } .
p
n
sp
n
n = 1
m N
\ N
We then have that
ˁ = V ( a )
V (
a )
= ʦ ( a )
ʦ (
a )
N
mn I { a n = a m } I { a n = a m }
1
2
s nm ) P m d ʱ
(1
sp
n
n = 1
m N
N
mn I { a n = a m }
I { a n = a m } .
1
2
P m d ʱ
(4.14)
p
n
sp
n
n = 1
m N
\ N
Since ʦ (
a )
ˆ
=
max a ʩ ʦ ( a )
ʦ ( a ) and V ( a )
=
max a ʩ V ( a )
V (
a ), we know
ˆ
from ( 4.14 ) that
N
mn I { a n = a m }
I { a n = a m }
1
2
s nm ) P m d ʱ
ˁ
(1
sp
n
 
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