Digital Signal Processing Reference
In-Depth Information
Example 2.6.3 Using the result from Example 2.6.1, find the PDF for the random
variable
Y ¼ 0
:
5 X þ 2
;
(2.153)
if X is a uniform random variable in [ 1, 1].
Solution From ( 2.153 ), we have:
y 1 ¼ 0
:
5 ð 1 Þþ 2 ¼ 2
:
5
;
(2.154)
y 2 ¼ 0
:
5 þ 2 ¼ 1
:
5
:
(2.155)
Using ( 2.154 ), ( 2.155 ), and ( 2.148 ), we arrive at:
8
<
1
y 1 y 2 ¼ 1
for
1 : 5 y 2 : 5 ;
f Y ðyÞ¼
(2.156)
:
0
otherwise
:
The input and output PDFs are shown in Fig. 2.33 .
Example 2.6.4 The random variable X is uniform in the interval [0, 1]. Find the
transformation which will result in an uniform random variable in the interval [ y 1 , y 2 ].
Solution From Example 2.6.1, it follows that the transformation is a linear trans-
formation
Y ¼ aX þ b;
(2.157)
where X is the given uniform random variable in the interval [0, 1], and the variable
Y is uniform in the interval [ y 1 , y 2 ].
From ( 2.157 ), using x 1 ¼ 0 and x 2 ¼ 1, we get:
y 1 ¼ ax 1 þ b ¼ b;
y 2 ¼ ax 2 þ b ¼ a þ b:
(2.158)
Fig. 2.33 Illustration of the linear transformation of the uniform random variable in Example
2.6.3
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