Digital Signal Processing Reference
In-Depth Information
Answer
We have:
1
e
t
2
e
jot
d
t ¼
2
1
0
e
t
2
cos
ðotÞ
d
t:
S
XX
ðoÞ¼
(7.159)
1
Using integral 3 from Appendix
A
to (
7.159
), we arrive at:
p
p
p
e
o
2
e
o
2
=
4
=
4
S
XX
ðoÞ¼
2
¼
:
(7.160)
2
Exercise E.7.9
Find the output PSD of the process
Y
(
t
) at the output of the RC filter
shown in Fig.
7.26
. Find PSD, mean value, and variance of the process
Y
(
t
).
Consider that a WS stationary process
X
(
t
) in the input of the filter has the
autocorrelation function
R
XX
ðtÞ¼
cos
ðo
0
tÞ;
(7.161)
where
o
0
is a constant.
Answer
The PSD of the process
X
(
t
) is (see (
7.56
)):
S
XX
ðoÞ¼pdðo þ o
0
Þþdðo o
0
Þ
½
:
(7.162)
The transfer function of the filter is:
joRC
1
þ joRC
:
HðjoÞ¼
(7.163)
The squared magnitude response is:
2
ðoRCÞ
2
j
HðjoÞ
j
¼
2
;
(7.164)
1
þðoRCÞ
or equivalently
2
ðoTÞ
2
j
HðjoÞ
j
¼
2
:
(7.165)
1
þðoTÞ
Fig. 7.26
RC filter in
Exercise E.7.9
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