Digital Signal Processing Reference
In-Depth Information
Answer We have:
1
e t 2 e jot d t ¼ 2 1
0
e t 2 cos ðotÞ d t:
S XX ðoÞ¼
(7.159)
1
Using integral 3 from Appendix A to ( 7.159 ), we arrive at:
p
p
p e o 2
e o 2
= 4
= 4
S XX ðoÞ¼ 2
¼
:
(7.160)
2
Exercise E.7.9 Find the output PSD of the process Y ( t ) at the output of the RC filter
shown in Fig. 7.26 . Find PSD, mean value, and variance of the process Y ( t ).
Consider that a WS stationary process X ( t ) in the input of the filter has the
autocorrelation function
R XX ðtÞ¼ cos ðo 0 tÞ;
(7.161)
where o 0 is a constant.
Answer The PSD of the process X ( t ) is (see ( 7.56 )):
S XX ðoÞ¼pdðo þ o 0 Þþdðo o 0 Þ
½
:
(7.162)
The transfer function of the filter is:
joRC
1 þ joRC :
HðjoÞ¼
(7.163)
The squared magnitude response is:
2
ðoRCÞ
2
j
HðjoÞ
j
¼
2 ;
(7.164)
1 þðoRCÞ
or equivalently
2
ðoTÞ
2
j
HðjoÞ
j
¼
2 :
(7.165)
1 þðoTÞ
Fig. 7.26 RC filter in
Exercise E.7.9
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