Digital Signal Processing Reference
In-Depth Information
In the expression (
7.123
), we can recognize the PSD
S
XX
(
o
):
1
R
XX
ðgÞ
e
jog
d
g:
S
XX
ðoÞ¼
(7.124)
1
Similarly, the second integral in (
7.123
) is a Fourier transform of the impulse
response
h
(
t
) of the filter, which is a transfer function of a filter
H
(
o
):
1
hðbÞ
e
job
d
b:
HðoÞ¼
(7.125)
1
Similarly, the first integral in (
7.123
) is:
1
hðaÞ
e
joa
d
a:
HðoÞ¼
(7.126)
1
Finally, placing (
7.124
)-(
7.126
) into (
7.123
), we arrive at:
S
YY
ðoÞ¼HðoÞHðoÞS
XX
ðoÞ:
(7.127)
Knowing that a magnitude characteristic of the filter can be expressed as:
2
HðoÞ
¼ HðoÞHðoÞ;
j
j
(7.128)
we get the final result for the output PSD
2
S
YY
ðoÞ¼ HðoÞ
j
j
S
XX
ðoÞ:
(7.129)
Note that the final result (
7.129
) is real because the PSD is a real function.
From (
7.129
), the average power of the output process is:
1
1
1
2
p
1
2
p
2
P
YY
¼
S
YY
ðoÞ
d
o ¼
j
HðoÞ
j
S
XX
ðoÞ
d
o:
(7.130)
1
1
Example 7.4.1
Find the mean power at the output of the filter shown in Fig.
7.19
,if
in the input is a white noise with the PSD equal to
N
0
/2.
Solution
The transfer function of the filter is:
1
1
þ jo
R
:
HðoÞ¼
(7.131)
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