Digital Signal Processing Reference
In-Depth Information
In the expression ( 7.123 ), we can recognize the PSD S XX ( o ):
1
R XX ðgÞ e jog d g:
S XX ðoÞ¼
(7.124)
1
Similarly, the second integral in ( 7.123 ) is a Fourier transform of the impulse
response h ( t ) of the filter, which is a transfer function of a filter H ( o ):
1
hðbÞ e job d b:
HðoÞ¼
(7.125)
1
Similarly, the first integral in ( 7.123 ) is:
1
hðaÞ e joa d a:
HðoÞ¼
(7.126)
1
Finally, placing ( 7.124 )-( 7.126 ) into ( 7.123 ), we arrive at:
S YY ðoÞ¼HðoÞHðoÞS XX ðoÞ:
(7.127)
Knowing that a magnitude characteristic of the filter can be expressed as:
2
HðoÞ
¼ HðoÞHðoÞ;
j
j
(7.128)
we get the final result for the output PSD
2
S YY ðoÞ¼ HðoÞ
j
j
S XX ðoÞ:
(7.129)
Note that the final result ( 7.129 ) is real because the PSD is a real function.
From ( 7.129 ), the average power of the output process is:
1
1
1
2 p
1
2 p
2
P YY ¼
S YY ðoÞ d o ¼
j
HðoÞ
j
S XX ðoÞ d o:
(7.130)
1
1
Example 7.4.1 Find the mean power at the output of the filter shown in Fig. 7.19 ,if
in the input is a white noise with the PSD equal to N 0 /2.
Solution The transfer function of the filter is:
1
1 þ jo R :
HðoÞ¼
(7.131)
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