Digital Signal Processing Reference
In-Depth Information
Exercise 5.6
(a) Find the probability that a random time between two consecutive Poisson
events with a constant intensity of
l
will be less than its mean value.
(b) Find the mean squared deviation from its mean value for the time interval
t
in
which
k
Poisson events occur.
Answer
(a) The time between two consecutive Poisson events is an exponential random
variable
X
. From (
5.65
),
EfXg¼
1
=l;
(5.224)
=lÞ¼
1
e
1
PfX<
1
=lg¼F
X
ð
1
¼
0
:
6321
:
(5.225)
(b) A mean squared deviation from a mean value is a variance of random variable.
The time interval in which
k
Poisson events occur is an Erlang's variable.
From (
5.90
), the variance of a Gamma variable is
b
l
2
:
s
2
¼
(5.226)
Replacing
b
with
k
in (
5.226
), we get the variance of Erlang's variable:
k
l
2
:
s
2
¼
(5.227)
Exercise 5.7
A random variable
X
has the PDF
f
X
ðxÞ¼
e
x
uðxÞ:
(5.228)
Find the PDF and mean value of the random variable
Y
if
aX
for
X
0
0
Y ¼
(5.229)
otherwise
a >
0
:
;
Answer
The PDF of the random variable
Y
is obtained from (2.138), as:
y
a
;
f
X
ð
x
Þ
a
f
X
ð
y
=
a
Þ
a
1
a
e
f
Y
ðyÞ¼
¼
¼
for
y
0
:
(5.230)
f
Y
ðyÞ¼
0
for
y<
0
;
(5.231)
The variable
X
is an exponential variable for which
l ¼
1. As a consequence,
EfXg¼
1
=l ¼
1
:
(5.232)
The mean value of the variable
Y
is:
EfYg¼EfaXg¼aEfXg¼a:
(5.233)
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