Digital Signal Processing Reference
In-Depth Information
Exercise 5.6
(a) Find the probability that a random time between two consecutive Poisson
events with a constant intensity of l will be less than its mean value.
(b) Find the mean squared deviation from its mean value for the time interval t in
which k Poisson events occur.
Answer
(a) The time between two consecutive Poisson events is an exponential random
variable X . From ( 5.65 ),
EfXg¼ 1
=l;
(5.224)
=lÞ¼ 1 e 1
PfX<
1
=lg¼F X ð 1
¼ 0
:
6321
:
(5.225)
(b) A mean squared deviation from a mean value is a variance of random variable.
The time interval in which k Poisson events occur is an Erlang's variable.
From ( 5.90 ), the variance of a Gamma variable is
b
l 2 :
s 2
¼
(5.226)
Replacing b with k in ( 5.226 ), we get the variance of Erlang's variable:
k
l 2 :
s 2
¼
(5.227)
Exercise 5.7 A random variable X has the PDF
f X ðxÞ¼ e x uðxÞ:
(5.228)
Find the PDF and mean value of the random variable Y if
aX for X 0
0
Y ¼
(5.229)
otherwise
a >
0
:
;
Answer The PDF of the random variable Y is obtained from (2.138), as:
y
a ;
f X ð x Þ
a
f X ð y = a Þ
a
1
a
e
f Y ðyÞ¼
¼
¼
for
y 0
:
(5.230)
f Y ðyÞ¼ 0
for
y<
0
;
(5.231)
The variable X is an exponential variable for which l ¼ 1. As a consequence,
EfXg¼ 1
=l ¼ 1
:
(5.232)
The mean value of the variable Y is:
EfYg¼EfaXg¼aEfXg¼a:
(5.233)
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