Digital Signal Processing Reference
In-Depth Information
From here,
p
2ln ð 0
x
s ¼
:
5 Þ
:
(5.206)
From ( 5.206 ), the median is found to be:
x ¼ 1
:
774 s:
(5.207)
Exercise 5.3 The random variable X is a Rayleigh variable with a parameter of s .
Find the variance of the random variable
Y ¼ 2 þ X 2
:
(5.208)
Answer The variance of the random variable Y is
Y 2
s 2
Y ¼ Y 2
:
(5.209)
From ( 5.208 ), the mean and the mean squared values are:
Y ¼ 2 þ X 2
;
(5.210)
2
Y 2
¼ð 2 þ X 2
¼ 4 þ X 4
þ 4 X 2
Þ
:
(5.211)
From ( 5.35 ), the mean squared value of Rayleigh variable X is
¼ 2 s 2
X 2
:
(5.212)
The fourth moment X 4 is obtained using the integral 4 from Appendix A ,
x 2
2 s 2 d x ¼
1
1
s 2
1
s 2 8 s 6
x 5 e
¼ 8 s 4
X 4
¼
:
(5.213)
0
Placing ( 5.212 ) into ( 5.210 ), we obtain:
Y ¼ 2 þ 2 s 2
:
(5.214)
Similarly,
¼ 4 þ 8 s 4
þ 8 s 2
Y 2
¼ 4 þ X 4
þ 4 X 2
:
(5.215)
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