Digital Signal Processing Reference
In-Depth Information
Placing ( 5.148 ) into ( 5.143 ), we get the probability that k events occur in the
interval t ,
k k
k !
k
¼ ð lt Þ
e k
e lt
PfX ¼ k; tg¼
:
(5.149)
k !
The probability ( 5.149 ) is another form of the Poisson formula ( 5.143 ) and thus
represents the probability mass function of a Poisson random variable.
Example 5.7.2 Telephone calls can come in to a telephone switching center with
the frequency of 0.5 calls/min. Find the probability that exactly two calls come in,
and the probability that no more than three calls come in.
Solution The number of calls that come in t ¼ 1 min, is a Poisson random variable
with the parameter l ¼ 0.5 calls/min.
From ( 5.149 ), we have:
5 2
2
0
:
e 0 : 5
PfX ¼ 2
; t ¼ 1 min
¼ 0
:
0758
:
(5.150)
!
; t ¼ 1 min X
3
PfX 3
P X ðk; tÞ
0
5 0
0
5 1
1
5 2
2
0
:
0
:
0
:
e 0 : 5
e 0 : 5
e 0 : 5
¼
þ
þ
!
!
!
5 3
3
0
:
e 0 : 5
þ
¼ 0
:
9982
:
(5.151)
!
5.7.3 Distribution and Density Functions
Using either
( 5.143 )or( 5.149 ),
the corresponding distribution and density
functions are:
F X ðxÞ¼ 1
0
PfX ¼ kguðx kÞ¼ 1
0
k k
k !
e k uðx kÞ
¼ 1
0
k
ðltÞ
e lt uðx kÞ;
(5.152)
k !
k k
k !
f X ðxÞ¼ 1
0
PfX ¼ kgdðx kÞ¼ 1
0
e k dðx kÞ
¼ 1
0
k
ðltÞ
e lt dðx kÞ:
(5.153)
k !
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