Digital Signal Processing Reference
In-Depth Information
Find the mean values of the sum and the product of variables X and Y .
Answer The mean value of the sum of random variables X and Y is:
EfX þ Yg¼EfXgþEfYg:
(4.204)
From ( 4.203 ), it follows:
EfXg¼ 3
:
(4.205)
The mean value of the uniform variable Y is at the point of symmetry of its
PDF, i.e.,
EfYg¼ 0
:
5
:
(4.206)
Placing ( 4.205 ) and ( 4.206 ) into ( 4.204 ), we get:
EfX þ Yg¼ 3 þ 0
:
5 ¼ 3
:
5
:
(4.207)
The random variables X and Y are independent, and as a consequence we have:
EfXYg¼EfXgEfYg:
(4.208)
Placing ( 4.205 ) and ( 4.206 ) into ( 4.208 ) we arrive at:
EfXYg¼ 1
:
5
:
(4.209)
Exercise 4.16 N messages are transmitted over a channel. The times necessary to
transmit the messages are the independent variables X i with equal mean values
m i ¼ m and equal variances s i ¼ s 2 .
(a) Find the density of a random time in which all messages could be transmitted.
(b) Find the approximate total time needed to transmit all N messages.
Answer
(a) According to the CLT, the total time needed to transmit all messages is
approximately equal to the normal random variable
X ¼ X
N
X i Nðm X ; s X Þ;
(4.210)
1
where
m X ¼ X
X ¼ X
N
N
s 2
s 2
i ¼ Ns 2
m i ¼ Nm ;
:
(4.211)
1
1
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