Digital Signal Processing Reference
In-Depth Information
Find the mean values of the sum and the product of variables
X
and
Y
.
Answer
The mean value of the sum of random variables
X
and
Y
is:
EfX þ Yg¼EfXgþEfYg:
(4.204)
From (
4.203
), it follows:
EfXg¼
3
:
(4.205)
The mean value of the uniform variable
Y
is at the point of symmetry of its
PDF, i.e.,
EfYg¼
0
:
5
:
(4.206)
Placing (
4.205
) and (
4.206
) into (
4.204
), we get:
EfX þ Yg¼
3
þ
0
:
5
¼
3
:
5
:
(4.207)
The random variables
X
and
Y
are independent, and as a consequence we have:
EfXYg¼EfXgEfYg:
(4.208)
Placing (
4.205
) and (
4.206
) into (
4.208
) we arrive at:
EfXYg¼
1
:
5
:
(4.209)
Exercise 4.16 N
messages are transmitted over a channel. The times necessary to
transmit the messages are the independent variables
X
i
with equal mean values
m
i
¼ m
and equal variances
s
i
¼ s
2
.
(a) Find the density of a random time in which all messages could be transmitted.
(b) Find the approximate total time needed to transmit all
N
messages.
Answer
(a) According to the CLT, the total time needed to transmit all messages is
approximately equal to the normal random variable
X ¼
X
N
X
i
Nðm
X
; s
X
Þ;
(4.210)
i¼
1
where
m
X
¼
X
X
¼
X
N
N
s
2
s
2
i
¼ Ns
2
m
i
¼ Nm
;
:
(4.211)
i¼
1
i¼
1
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