Digital Signal Processing Reference
In-Depth Information
This result shows us that if the random variables are independent, we
can obtain the joint density from the marginal densities.
A.3.3. Let us suppose that
Pfx
1
< X
1
x
1
þ
d
x
1
; x
2
< X
2
x
2
þ
d
x
2
g¼Pfy
1
< Y
1
y
1
þ
d
y
1
; y
2
< Y
2
y
2
þ
d
y
2
g:
(3.350)
From (
3.350
), we have:
f
X
1
X
2
ðx
1
; x
2
Þ
d
x
1
d
x
2
¼ f
Y
1
Y
2
ðy
1
; y
2
Þ
d
y
1
d
y
2
:
(3.351)
Knowing that the random variables
X
1
and
X
2
are independent, we get:
f
X
1
ðx
1
Þf
X
2
ðx
2
Þ
d
x
1
d
x
2
¼ f
Y
1
Y
2
ðy
1
; y
2
Þ
d
y
1
d
y
2
:
(3.352)
The joint distribution of
Y
1
and
Y
2
is:
y
1
ð
y
2
ð
gðx
1
Þ
ð
gðx
2
Þ
ð
F
Y
1
Y
2
ðy
1
;y
2
Þ¼
f
Y
1
Y
2
ðy
1
;y
2
Þ
d
y
1
d
y
2
¼
f
X
1
X
2
ðx
1
;x
2
Þ
d
x
1
d
x
2
1
1
1
1
gðx
1
Þ
ð
gðx
2
Þ
ð
y
1
ð
y
2
ð
¼
f
X
1
ðx
1
Þf
X
2
ðx
2
Þ
d
x
1
d
x
2
¼
f
X
1
ðx
1
Þ
d
x
1
f
X
2
ðx
2
Þ
d
x
2
¼F
Y
1
ðy
1
ÞF
Y
2
ðy
2
Þ:
1
1
1
1
(3.353)
The joint distribution function is equal to the product of the marginal
distributions. As a consequence, the variables
Y
1
and
Y
2
are independent.
A.3.4. The conditional distribution can be rewritten as:
P
f
X
1
x
1
;
X
2
x
2
g
PfX
2
x
2
g
F
X
1
X
2
ð
x
1
;
x
2
Þ
F
X
2
ðx
2
Þ
F
X
1
ðx
1
jX
2
x
2
Þ¼
¼
:
(3.354)
If the random variables
X
1
and
X
2
are independent, then
F
X
1
X
2
ðx
1
; x
2
Þ¼F
X
1
ðx
1
ÞF
X
2
ðx
2
Þ;
(3.355)
resulting in:
F
X
1
ð
x
1
Þ
F
X
2
ð
x
2
Þ
F
X
2
ðx
2
Þ
F
X
1
ðx
1
jX
2
x
2
Þ¼
¼ F
X
1
ðx
1
Þ:
(3.356)
If the random variables
X
1
and
X
2
are independent, then the conditional
distribution of variable
X
1
, given the other variable
X
2
, is equal to the
marginal distribution of
X
1
.
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