Digital Signal Processing Reference
In-Depth Information
Answer
From (
3.238
), we have:
PfX
1
¼ x
11
g¼
X
3
PfX
1
¼ x
11
; X
2
¼ x
2
j
g¼
0
:
1
þ
0
:
15
þ
0
:
2
¼
0
:
45
:
j¼
1
PfX
1
¼ x
12
g¼
X
3
PfX
1
¼ x
12
; X
2
¼ x
2
j
g¼
0
:
15
þ
0
:
25
þ
0
:
15
¼
0
:
55
:
(3.239)
j¼
1
The marginal distribution and density are, respectively:
F
X
1
ðx
1
Þ¼
0
:
45
uðx
1
1
Þþ
0
:
55
uðx
1
þ
1
Þ;
(3.240)
f
X
1
ðx
1
Þ¼
0
:
45
dðx
1
1
Þþ
0
:
55
dðx
1
þ
1
Þ:
(3.241)
Similarly,
PfX
2
¼ x
21
g¼
X
2
PfX
1
¼ x
1
j
; X
2
¼ x
21
g¼
0
:
1
þ
0
:
15
¼
0
:
25
;
j¼
1
PfX
2
¼ x
22
g¼
X
2
PfX
1
¼ x
1
j
; X
2
¼ x
22
g¼
0
:
15
þ
0
:
25
¼
0
:
4
;
j¼
1
PfX
2
¼ x
23
g¼
X
2
PfX
1
¼ x
1
j
; X
2
¼ x
23
g¼
0
:
2
þ
0
:
15
¼
0
:
4
;
(3.242)
j¼
1
F
X
2
ðx
2
Þ¼
0
:
25
uðx
2
Þþ
0
:
4
uðx
2
2
Þþ
0
:
35
uðx
2
5
Þ:
(3.243)
f
X
2
ðx
2
Þ¼
0
:
25
dðx
2
Þþ
0
:
4
dðx
2
2
Þþ
0
:
35
dðx
2
5
Þ:
(3.244)
Exercise 3.6
Find the conditional distributions,
F
X
1
x
1
jX
2
¼ x
21
¼
0
ð
Þ;
and
F
X
2
x
2
jX
1
¼ x
11
¼
1
ð
Þ;
(3.245)
for the random variables from Exercise 3.5.
Answer
From (
3.46
), we have:
P
2
i
¼
1
PfX
1
¼ x
1
i
; X
2
¼ x
21
¼
0
guðx
1
x
1
i
Þ
PfX
2
¼ x
21
¼
0
g
F
X
1
x
1
jX
2
¼ x
21
¼
0
ð
Þ ¼
:
(3.246)
From (
3.238
), we have:
PX
1
¼
1
f
; X
2
¼
0
g ¼
0
:
1
;
PX
1
¼
1
f
; X
2
¼
0
g ¼
0
:
15
:
(3.247)
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