Digital Signal Processing Reference
In-Depth Information
Using (
2.387
), we get:
1
1
2
p
f
X
2
ðoÞ
e
joðyx
1
Þ
d
o ¼ f
X
2
ðy x
1
Þ;
(3.214)
1
From (
3.213
) and (
3.214
), we arrive at:
1
f
Y
ðyÞ¼
f
X
1
ðx
1
Þf
X
2
ðy x
1
Þ
d
x
1
:
(3.215)
1
This expression can be rewritten as:
1
f
Y
ðyÞ¼
f
X
2
ðx
2
Þ f
X
1
ðy x
2
Þ
d
x
2
:
(3.216)
1
The expressions (
3.215
) and (
3.216
) present the convolution of the PDFs of
random variables
X
1
and
X
2
, and can be presented as:
f
Y
ðyÞ¼f
X
1
ðx
1
Þf
X
2
ðx
2
Þ¼f
X
2
ðx
2
Þf
X
1
ðx
1
Þ;
(3.217)
where * stands for the convolution operation.
This result can be generalized for the sum of
N
independent variables
X
i
,
Y ¼
X
N
X
i
;
(3.218)
i¼
1
f
Y
ðyÞ¼f
X
1
ðx
1
Þf
X
2
ðx
2
Þf
X
N
ðx
N
Þ:
(3.219)
Example 3.5.3
Two resistors
R
1
and
R
2
are in a serial connection (Fig.
3.16a
). Each
of them randomly changes its value in a uniform way for 10% about its nominal
value of 1,000
. Find the PDF of the equivalent resistor
R
,
O
R ¼ R
1
þ R
2
(3.220)
if both resistors have uniform density in the interval [900, 1,100]
.
O
Solution
Denote the equivalent resistor
R
as a random variable
X
and the particular
resistors
R
1
and
R
2
, as the random variables
X
1
and
X
2
. Then,
X ¼ X
1
þ X
2
:
(3.221)
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