Digital Signal Processing Reference
In-Depth Information
If the random variables
X
1
and
X
2
are independent, then the joint characteristic
function of their sum is equal to the product of the marginal characteristic functions,
f
Y
ðoÞ¼f
X
1
ðoÞf
X
2
ðoÞ:
(3.201)
This result can be applied for the sum of
N
independent random variables
X
i
,
Y ¼
X
N
X
i
:
(3.202)
i¼
1
The joint characteristic function of (
3.202
)is
f
Y
ðoÞ¼
Y
N
f
X
i
ðoÞ:
(3.203)
i¼
1
Example 3.5.1
Find the characteristic function of the random variable
Y
, where
Y ¼ aX
1
þ bX
2
(3.204)
and where
X
1
, and
X
2
are independent.
Solution
Using (2.386) and the definition of the characteristic function (
3.194
) and
the condition of independence (
3.201
), we have:
f
Y
ðoÞ¼Ef
e
joðaX
1
þbX
2
Þ
g¼Ef
e
joaX
1
gEf
e
jobX
2
g¼f
X
1
ðaoÞf
X
2
ðboÞ:
(3.205)
Example 3.5.2
The random variables
X
1
and
X
2
are independent. Find the joint
characteristic function of the variables
X
and
Y
, as given in the following equations:
X ¼ X
1
þ
2
X
2
;
Y ¼
2
X
1
þ X
2
:
(3.206)
Solution
From the definition (
3.194
), and using (
3.206
), we have:
f
XY
ðo
1
; o
2
Þ¼Ef
e
jðo
1
Xþo
2
Y
g¼Ef
e
jo
1
ðX
1
þ
2
X
2
Þþjo
2
ð
2
X
1
þX
2
Þ
g
¼ Ef
e
jX
1
ðo
1
þ
2
o
2
ÞþjX
2
ð
2
o
1
þo
2
Þ
g:
(3.207)
Knowing that the random variables
X
1
and
X
2
are independent from (
3.207
) and
(
3.201
), we arrive at:
f
XY
ðo
1
; o
2
Þ¼Ef
e
jX
1
ðo
1
þ
2
o
2
Þ
gEf
e
jX
2
ð
2
o
1
þo
2
Þ
g
¼ f
X
1
ðo
1
þ
2
o
2
Þf
X
2
ð
2
o
1
þ o
2
Þ:
(3.208)
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