Digital Signal Processing Reference
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for three cases (Fig. 2.70b ):
(a) X is uniform in the interval [ 2, 1]
(b) X is uniform in the interval [0, 2]
(c) X is uniform in the interval [2, 4],
Answer
(a) The random variable Y is a mixed variable that has the discrete value y ¼ 0, and
it is continuous in the range [0, 1].
PfY ¼ 0 g¼PfX <
0 2
=
3
:
(2.516)
For 0
< x <
1, the output random variable Y is continuous and equal to X ,
resulting in:
f Y ðyÞ¼f X ðxÞ¼ 1
=
3
:
(2.517)
From ( 2.516 ) and ( 2.517 ), we arrive at:
2
=
3 dðyÞþ 1
=
30
y 1
;
f Y ðyÞ¼
(2.518)
0
otherwise
:
(b) The random variables X and Y are both positive and, from ( 2.515 ), the random
variable is equal to X in the interval [0, 2].
=
20
y 2
;
1
f Y ðyÞ¼
(2.519)
:
0
otherwise
(c) The random variable Y is equal to X in the interval [2, 4]
Y ¼ X
for
2 x 4
(2.520)
and
1
=
22
y 4
;
f Y ðyÞ¼
(2.521)
0
otherwise
:
Exercise E.2.18 The discrete random variable X has discrete values 1, 2, 3, 6,
and 8, with the corresponding probabilities:
PfX ¼ 1 g¼PfX ¼ 8 0
:
1
;
PfX ¼ 2 g¼PfX ¼ 3 0
:
3
;
PfX ¼ 6 0
:
2
:
(2.522)
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