Digital Signal Processing Reference
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However, the r.v. X is less than 3 if it is equal to either 1 or 2, resulting in:
PfX <
3 0
:
25 þ 0
:
25 ¼ 0
:
5
:
(2.460)
This probability corresponds to the value of the distribution in the distribution
plot for x ¼ 3 and to the area below delta functions from 1 until 3 in the PDF
plot, i.e., again equal to 0.5.
Exercise E.2.5 The PDF of the random variable X is given in Fig. 2.59a . Find the
type of the random variable and plot the corresponding distribution function. Find
the probability that the random variable is equal to 1 and to 2, as well. Additionally,
find the probability that the random variable is greater than 1.
Answer The random variable is mixed (i.e., it is continuous in the interval [0, 2]
and has one discrete value X ¼ 2, indicated by the delta function in point 2 of the
PDF plot). The corresponding distribution function is the integral of the PDF, as
demonstrated in Fig. 2.59b .
The r.v is continuous in the interval [0, 2] and thus it does not take any particular
value in this interval, resulting in:
PfX ¼ 1 0
:
(2.461)
However, the random variable takes the discrete value 2 with the probability
equal to 1/4
PfX ¼ 2 1
=
4
:
(2.462)
Similarly, we have:
ð
2
3
8 þ
1
4 ¼
5
8 :
PfX>
1
f X ðxÞ d x ¼
(2.463)
1
Fig. 2.59 ( a ) PDF and ( b ) distribution of the mixed random variable
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