Digital Signal Processing Reference
In-Depth Information
Similarly, the second integral in (
2.294
) is:
1
xdðx
1
Þ
d
x ¼
1
(2.296)
1
From (
2.294
)to(
2.296
), we have:
m
X
¼
0
:
5
0
þ
0
:
5
1
¼
0
:
5
:
(2.297)
Note that this is the same result as in Example 2.7.2
The next example illustrates that the general expression (
2.261
) can also be used
in the calculation of the mean value for a mixed random variable.
Example 2.7.14
Consider a mixed random variable with the density function:
8
<
1
3
dðxÞ
for
x ¼
0
;
2
3
x
for
0
< x
1
;
f
X
ðxÞ¼
(2.298)
:
2
3
ðx
2
Þ
for
1
x
2
;
0
otherwise
:
From (
2.261
) and (
2.298
), we have:
1
1
ð
ð
1
2
x
3
dðxÞ
d
x þ
2
x
2
3
d
x þ
2
x
ð
x
2
Þ
3
EfXg¼
xf
X
ðxÞ
d
x ¼
d
x:
(2.299)
1
1
0
1
Knowing that
1
xdðxÞ
d
x ¼
0
(2.300)
1
the first integral in the right side of (
2.299
) is equal to zero, that is:
1
x
3
dðxÞ
d
x ¼
0
(2.301)
1
The second integral on the right side of (
2.299
) is:
ð
1
1
0
¼
2
x
2
3
d
x ¼
2
x
3
9
2
9
:
(2.302)
0
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