Chemistry Reference
In-Depth Information
8.509
˚
). Ru(1)O
4
tetrahedra -
brown
,Ru(2)O
4
tetrahedra -
Fig. 8 (a) The structure of RuO
4
(
a
¼
8.595
˚
). Os(2)F
4
tetrahedra -
grey
, Os(1)(F/O)
4
tetrahedra
-
red
, F atoms -
green
, F/O atoms -
yellow
pink
. O atoms -
blue
.(b)OsF
2
O
2
(
a
¼
-He]
56
and [(Nb
3
)
2
(Nb
3
)
6
][
to each of the eight Nb atoms to give [
C
C
-O]
32
.
Nb
3
is
-Ru(2).
For the OsF
2
O
2
structure, we take as parent the hypothetical Li
56
[Re
2
Re
6
]N
32
.
Justification for this is that the compound Li
56
[Mn
2
Mn
6
]N
32
does exist, and Re is in
the same group. We require 48 electrons to convert the 32 N atoms to 16 [
C
-Ru, and so we have [
C
-RuO
4
] with both
C
-Ru(1) and
C
C
-O]
and16 [
C
-F] atoms and the remaining 8 from the 56 Li atoms to convert the Re to
C
-[Os(F
2
)(O
2
)]. The resulting structure
involves a body-centred cube comprising two Os(2)F
4
tetrahedra, the inscribed
icosahedron being formed by six Os(1)(F/O)
4
tetrahedra.
-Os. The nett result is [
C
-He]
56
plus
C
3.2.3 Sodalite and Danalite
Another substructure of Li
56
[V(1)
2
V(2)
6
]N
32
is that of the sodalite type typified by
V(2)
6
]N
32
, where the V(2)N
4
tetrahedra correspond with SiO
4
tetrahedra, Na(2)N
4
tetrahedra with AlO
4
tetrahedra and V(1)N
4
tetrahedra with ClO
4
tetrahedra
In rationalizing this substructure, we begin with the parent structure,
Na
56
[P(1)
2
P(2)
6
]N
32
(note the substitution of Li atoms by the Na atoms of the
original sodalite). First, we convert the 32 N atoms to 32[
-O] by the acceptance of
32 electrons from 32 Na atoms, leaving 24 Na atoms plus 32 [
C
-Ne]. The formula
becomes Na
24
[
C
-O]
32
. Within the [P(1)
2
P(2)
6
] group, we
now have 2P(1) atoms accept 2e each from Na to form 2[
C
-Ne]
32
[P(1)
2
P(2)
6
][
C
C
-Cl], and we then
associate with 2[
C
-Cl] eight of the 32[
C
-O] atoms to form 2[
C
-ClO
4
]: the pseudo-
formula is now Na
20
[
C
-Ne]
36
[[
C
-ClO
4
]
2
P(2)
6
][
C
-O]
24
, which we rewrite as
Na
14
[
-ClO
4
]
2
. We need now to convert [Na
6
P(2)
6
]
to [Al
6
Si
6
], and this requires that the 6 P(2) atoms donate 1e each and the six Na
atoms accept 2e each, a net acceptance of 6e for the group, leading to a final
pseudo-formula Na
8
[
C
-He]
36
[Na
6
P(2)
6
][
C
-O]
24
[
C
C
-Ne]
42
[Al
6
Si
6
][
C
-O]
24
[
C
-ClO
4
]
2
, a neon-stuffed sodium
perchlorate sodalite.