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Exercise 8.12. Let f W .0; 1/ ! IR be a continuous function. Show that if
Z 1
f.x/ dx D 0
0
and
f.x/ 0 for x 2 .0; 1/;
then f.x/ D 0 for all x 2 .0; 1/.
˘
Exercise 8.13. (a) Assume that q is a non-negative function defined on the unit
interval Œ0; 1 and that the integral of q is small. That is, q.x/ 0 for x 2 Œ0; 1
and
Z 1
q.x/ dx ;
0
where is a small positive number. We want to study the size of the set where q
is “fairly” large. To this end, consider the set
S Df x 2 Œ0; 1 I q.x/ p g :
We will assume that q is such that S consists of a countable disjoint union of
intervals, i.e.,
[
.a i ;b i / \ .a j ;b j / D; for i ¤ j:
S D
Œa i ;b i ;
i D 1
The length j S j of S is defined in a straightforward manner as
j S jD X
i D 0
a i /:
.b i
Show that
j S j p :
(b) Solve the problem ( 8.1 )-( 8.3 ) in the case of
u .x; 0/ D f.x/ D 8:1 sin.3x/:
(c) Solve the problem ( 8.12 )-( 8.14 ) in the case of
v .x; 0/ D g.x/ D 8 sin.3x/:
(d) Compute
Z 1
.f .x/ g.x// 2 dx:
0
 
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