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Let us choose x 0
D 1:0 and compute approximations to the solution of ( 4.77 )
using the iteration
x kC1 D sin.x k =10/:
(4.78)
We get the following results:
x 0 D 1:0;
x 1 D 0:09983;
x 2 D 0:00998;
x 3 D 0:00099;
which seems to converge nicely toward x D 0 being the solution of ( 4.77 ). For this
particular problem, we can understand this behavior by observing that, for small x, 3
sin.x=10/ x=10;
(4.79)
and thus, from ( 4.78 ),
x kC1 x k =10;
(4.80)
so
x k .1=10/ k ;
(4.81)
which certainly converges toward zero.
4.5.1
Convergence of Fixed-Point Iterations
We have seen that an equation of the form
v D h. v /
(4.82)
can sometimes be solved by an iteration of the form
v kC1 D h. v k /:
(4.83)
3 The Taylor series of the sine function gives
y C O .y 3 /:
sin.y/
D
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